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I think it must be like this.... 360 degrees divided by 30 = 12 = the position of each corner point in relation to the next (from the centre of a circle using a protractor) and the measurement of a single exterior angle 12 degrees times 30 = 360 degrees = the measures of all the exterior angles together ) if that's what you wanted)

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Q: The sum of the measures of the exterior angles of a 30-gon?
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