I think it must be like this.... 360 degrees divided by 30 = 12 = the position of each corner point in relation to the next (from the centre of a circle using a protractor) and the measurement of a single exterior angle 12 degrees times 30 = 360 degrees = the measures of all the exterior angles together ) if that's what you wanted)
What is the sum of the measures of the exterior angles of a regular polygon with ten sides
1 a circle 360 interior angles 360 exterior agles
Measures of what? The interior angles, the exterior angles, the lengths of sides?
The sum of the exterior angles of ANY polygon, convex or concave, is 360 degrees.
If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.
The sum of the measures of the exterior angles of an octagon (and any polygon) is 360o.
360 degrees. The sum of the measures of the exterior angles of any polygon is 360°.
What is the sum of the exterior angles of a 23 gon
What is the sum of the measures of the exterior angles of a regular polygon with ten sides
1 a circle 360 interior angles 360 exterior agles
Measures of what? The interior angles, the exterior angles, the lengths of sides?
The sum of the exterior angles of ANY polygon, convex or concave, is 360 degrees.
The sum of a regular polygons exterior angles always = 360
If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.
A 4 sided quadrilateral has interior angles that add up to 360 degrees and its exterior angles add up to 360 degrees
It depends on what the measures relate to: lengths of sides, interior angles, exterior angles, ...
540 degrees