Since it is centres at the origin (0,0).
The the displacement of (x,y) is zero.
The radius is '3'
Using Pythagoras.
x^2 + y^2 = r^2
We have
(x - 0)^2 + (y - 0 )^2 = 3^2
Since thre 'zeroes' are trivial we can discount them .
Hence
x^2 + y^2 = 3^2 is the circle equ'n.
x2 + y2 = 25
x2 + y2 = 25
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
x2/52 + y2/93 = 1
bx2/14 +y2/25 =1
x2 + y2 = 25
x2 + y2= 16
x2 + y2 = 25
x2 + y2 = 36
x2 + y2 = 49
The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.The equation of a circle centered at the origin is x2 + y2 = r2; in this case, x2 + y2 = 64.
Since the circle is centered at the origin, the equation of the circle is x2 + y2 = r2. So we have: x2 + y2 = (3/2)2 x2 + y2 = 9/4
Equation of circle: (x+2)^2 +(y+3) = 49
Equation of circle: (x-3)^2 +(y-2)^2 = 49
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
1.6667