120
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To answer this simply try a few out for yourself. In a 2x1 cm rectangle, the area is 2 cm squared and the perimeter is 6 cm In a 12x10 rectangle, the area is 120 cm squared and the perimeter is 44 cm. In some cases, the perimeter is larger and in others it is smaller. To answer your question, no, the perimeter of a rectangle is NOT always greater than its area.
12cm a decagon is 10 sides 120/10=12
Not enough information. This means that there are many solutions. Therefore, the most complete way to give an answer is in the form of a formula. Set the definition of W and L to: W = width of rectangle L = length of rectangle 2W + 2L = 120 [Perimeter of 120 = (Length*2) + (Width*2)] Which simplifies to {W = 60-L | 0 < L <60} (values for X and Y have to be between 0 and 60, but not exactly 0 or 60) So replace L (length) in the simplified formula with any number that is between 0 and 60. Subtract this number from 60 to determine the corresponding width. For example, I can replace L with 40, and the equation becomes W = 60-40 Simplifies to W = 20 So, one possible solution is W=20 and L=40.
The answer is indeterminate, because there are many different rectangles, with different perimeters, whose area can equal 120. Some examples (area being length X width, and perimeter being 2 X length + 2 X width): * Where L=20 & W=6, A=120 and P=40+12=52. * Where L=30 & W=4, A=120 and P=60+8=68. * Where L=60 & W=2, A=120 and P=120+4=124.
Perimeter = 120+60+120+60 = 360 yards
The perimeter is 120 cm
Suppose there are R rectangles and T trapezoids. Then R + T = 540 and T = R + 120 Substituting this value of T in the previous equation gives R + (R + 120) = 540 or 2R + 120 = 540 so that 2R = 420 or R = 210. Then T = R + 120 gives T = 210 + 120 = 330.
If the asker is referring to area, the answer is 120 feet. Area = base times height (A=bh) A=(12)(10)=120 If the asker is referring to perimeter, then the answer is 44 feet. Since rectangles have 2 sets of congruent sides, perimeter can be defined as 2(Width+length) P=2(10+12)=2(22)=44
120
how do you construct a triangle which has a perimeter of 120 and the base angles abc be 30 and 45 degrees
Very interesting question. The answer is: There is no answer, because knowingthe area doesn't tell you the shape or the perimeter.There are an infinite number of rectangles that all have the same area butdifferent perimeters.The shortest perimeter that can enclose 120 acres is a circle, with diameter ofabout 2,580 ft, or 0.4886 mile. The perimeter (circumference) is 1.535 mile. (rounded)The rectangle with the shortest perimeter that encloses 120 acres is a squarewith sides of 2,286-ft. The perimeter is 9,145-ft or 1.732 miles.The perimeter can be anything greater than that. The more long and skinny and"unsquare" the rectangle is, the longer the perimeter is, for the same area.Examples:1,800-ft x 2,904-ftArea = 120 acresPerimeter = 9,408-ft = 1.782 miles1,452-ft x 3,600-ft:Area = 120 acresPerimeter = 10,105-ft = 1.914 miles726-ft x 7,200-ft:Area = 120 acresPerimeter = 15,862-ft = 3.002 miles242-ft x 21,600-ftArea = 120 acresPerimeter = 43,684-ft = 8.273 miles60.5-ft x 86,400-ftArea = 120 acresPerimeter = 172,921-ft = 32.750 miles
Perimeter = 8*15 = 120 cm
It is: 120+80+120+80 = 400 feet
120 is possible
The answer depends on what the 120 ft refers to. Is it a measure of a side, a diagonal or is 120 ft the perimeter and you wish to minimise something else?