The answer is indeterminate, because there are many different rectangles, with different perimeters, whose area can equal 120. Some examples (area being length X width, and perimeter being 2 X length + 2 X width): * Where L=20 & W=6, A=120 and P=40+12=52. * Where L=30 & W=4, A=120 and P=60+8=68. * Where L=60 & W=2, A=120 and P=120+4=124.
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P = 46 cm A = 120 sq cm
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
yes it can; a rectangle 5 by 2 has perimeter 14 and area 10 for example; a rectangle 10 by 2 has perimeter 24 and area 20, both greater.
Of course, a rectangle can have a greater perimeter and a greater area. Simply double all the sides: the perimeter is doubled and the area is quadrupled - both bigger than they were.
The perimeter of a rectangle is the distance around the rectangle. The area of a rectangle is the space inside the rectangle. To calculate either one you need the length and the width of the rectangle. To calculate the area multiply the length times the width. To calculate the perimeter add the length+width+length+width (that is the distance all the way around)