Not enough information. This means that there are many solutions.
Therefore, the most complete way to give an answer is in the form of a formula.
Set the definition of W and L to:
W = width of rectangle
L = length of rectangle
2W + 2L = 120 [Perimeter of 120 = (Length*2) + (Width*2)]
Which simplifies to
{W = 60-L | 0 < L <60}
(values for X and Y have to be between 0 and 60, but not exactly 0 or 60)
So replace L (length) in the simplified formula with any number that is between 0 and 60. Subtract this number from 60 to determine the corresponding width.
For example, I can replace L with 40, and the equation becomes
W = 60-40
Simplifies to
W = 20
So, one possible solution is W=20 and L=40.
10 by 50, 15 by 45, 20 by 40.
dont know dont care
4 x 4 and 6 x 3
area 63 and perimeter is 32
Rectangles Perimeter Is 2L + 2W. 2(7) + 2(4) = Perimeter 14 + 8 = Perimeter Perimeter = 22
2l+2w
It is a 3 x 15 rectangle !
10 by 50, 15 by 45, 20 by 40.
You can't tell the dimensions from the perimeter. There are an infinite number of different rectangles, all with different lengths and widths, that all have the same perimeter.
You can't tell the dimensions from the perimeter. There are an infinite number of rectangles, with different dimensions, that all have the same perimeter. If it's 168, then the only thing you can be sure of is that the length and width add up to 84, but you can't tell what either of those dimensions must be.
No, it is not. I'll give you two examples of a rectangle with a perimeter of 1. The first rectangle has dimensions of 1/4x1/4. The area is 1/16. The second rectangle has dimensions of 3/8x1/8. The area is 3/64. You can clearly see that these two rectangles have the same perimeter, yet the area is different.
The answer depends on what the 120 ft refers to. Is it a measure of a side, a diagonal or is 120 ft the perimeter and you wish to minimise something else?
dont know dont care
4 x 4 and 6 x 3
The area doesn't tell you the dimensions or the perimeter. It doesn't even tell you the shape. -- Your area of 36 cm2 could be a circle with a diameter of 6.77 . (Perimeter = 21.27.) -- It could be a square with sides of 6 . (Perimeter = 24.) -- It could be rectangles that measure 1 by 36 (Perimeter = 74) 2 by 18 (Perimeter = 40) 3 by 12 (Perimeter = 30) 4 by 9 (Perimeter = 26). There are an infinite number of more rectangles that it could be, all with the same area but different perimeters.
There is an infinite number that can have that perimeter
10cm by 10cm (perimeter=40cm), 5cm by 20cm (perimeter=50cm), 50cm by 2cm (perimeter=104cm), 100cm by 1cm (perimeter=202cm). All of these rectangles' areas are 100cm2