The answer will depend on the dimensions of the 2 squares
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Pythagoras.
Isosceles triangles have two sides which are the same length and two angles which are equal. So if your right triangle has one side of length 2 feet, which is not the hypotenuse, then the remaining side must also be 2 feet long. We know that the square of the length of the hypotenuse is equal to the squares of the other two sides. 2 squared is 4. So the squares of the two sides are 4 + 4 which equals 8. Now we just find the square root of 8, which is 2.8284... So the length of the hypotenuse is 2.83 Feet (to two decimal places). Or, In a right isosceles triangle, the two base angles equal 45°. Since the length leg is 2 ft, then the hypotenuse length would be equal to 2√2 or approximately to 2.83 ft. sin 45° = leg/hypotenuse hypotenuse = 2/sin 45° hypotenuse = 2/(√2/2) hypotenuse = 4/√2 hypotenuse = 4√2/2 hypotenuse = 2√2 °
5 squares. One 2 by 2 square and four 1 by 1 squares.
The Pythagorean theorem states that the length of the hypotenuse of a right triangle is the square root of the sum of the squares of the other two sides.[(24 in)^2 + (7 in)^2]^(1/2) = 25 in
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 and a vertical distance y2-y1 . The square root of the squares gives the diagonal (hypotenuse). In this case, the y difference is 0, so the distance is simply the x change of 4.