The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 and a vertical distance y2-y1 . The square root of the squares gives the diagonal (hypotenuse).
In this case, the y difference is 0, so the distance is simply the x change of 4.
0 0
8.54
Points: (2, 4) and (5, 0) Distance: 5
Points: (-5, -2) and (3, 13)Distance works out as 17 units
The distance between two points is Square root of [ (difference in their 'x' coordinates)2 + (difference in their 'y' coordinates)2 ]
0 0
10
8.54
If the points are (3, 2) and (9, 10) then the distance works out as 10
To find the distance between two points on a graph, you can use the distance formula: √((x₂ - x₁)² + (y₂ - y₁)²). Plug in the coordinates of the two points to calculate the distance.
the distance between two points is length
The distance between the points of (4, 3) and (0, 3) is 4 units
11 points
Points: (-6, 1) and (-2, -2) Distance: 5 units
Points: (2, 2) and (8, -6) Distance: 10
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
length