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What are the dimensions of a rectangle which has an area of 72cm2 and perimeter of 44 cm?
Wiki User
∙ 14y ago
Suppose the Length and Width are L and W.
Then Perimeter: 2(L + W) = 44 so that L + W = 22 and W = 22 - L
and Area: L*W = 72 so that L*(22 - L) = 72
ie L2 - 22L + 72 = 0
(L - 4) (L - 18) = 0
Then L = 4 giving W = 18 or L = 18 giving W = 4
Since L > W (by convension), the answer is L =18 cm and W = 4 cm
Substituting the
Wiki User
∙ 14y ago
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