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Let the diagonals be x and y and so:-

If: x+y = 11.55 then y = 11.55-x

Area: 0.5*x*y = 16.335 => x*(11.55-x) = 16.335*2

So: 11.55x-x^2 = 32.67 => 11.55x-x^2 -32.67 = 0

Solving the above quadratic equation: x = 4.95 or x = 6.6

Therefore by substitution its diagonals are: 4.95 cm and 6.6 cm

Check: 4,95+6.6 = 11.55 cm which is the sum of its diagonals

Check: 0.5*4.95*6.6 = 16.335 square cm which is its area

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