It looks like a circle
The name of a 40 sided polygon is Tetracontagon.
The interior angles of a 40 sided polygon add up to 6840 degrees
The sum of the interior angles of a convex polygon with n sides is given by (n-2)x180o. So for a 40 sided polygon n=40; thus (40-2)x180o = 38x180o = 6840o.
Each central angle of a regular 9 sided polygon: 360/9 = 40 degrees
At every 9 degree turn it will look the same then after 40 turns it will map back on itself.
The name of a 40 sided polygon is Tetracontagon.
A 40-sided polygon has 40 sides. Count again, to be sure.
tetracontahedron
If its a regular 9 sided polygon then the exterior angles are 40 degrees.
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
It is called Tetracontagon.
40-gon.
The interior angles of a 40 sided polygon add up to 6840 degrees
I find the name "30-sided polygon", "40-sided polygon", etc. just fine.
The sum of the interior angles of a convex polygon with n sides is given by (n-2)x180o. So for a 40 sided polygon n=40; thus (40-2)x180o = 38x180o = 6840o.
In a regular 40-sided polygon (also known as a tetracontagon), each interior angle can be calculated using the formula ((n-2) \times 180^\circ / n), where (n) is the number of sides. For a 40-sided polygon, this yields ((40-2) \times 180^\circ / 40 = 38 \times 180^\circ / 40 = 171^\circ). Therefore, each interior angle in a regular 40-sided polygon measures 171 degrees.
A 40 sided polygon is call a Tetracontagon. Try saying that ten times fast. :) Hope this helped.