L x B which gives the area of th rectangle then remaining we will have 4 equator triangle 1/3BH3 is the are for the triangle. cumulatively we will get area for the hexagan.
The total number of diagonals for a convex (or concave) polygon, a hexagon being of the former type, is given by the equation (n2 - 3n)/2, where n is the number of sides of the polygon. A hexagon has 6 sides, so plugging the number 6 into the above equation for n, one finds that a hexagon has: [62 - 3(6)]/2 = (36 - 18)/2 = 18/2 = 9 diagonals.
A rectangle would fit the given description
The number of diagonals in an n-sided polygon is given by nC2 - n (where n is the number of sides of the polygon) or in the expanded form: factorial (n) _______________________ {factorial (2) * factorial (n-2)} substituting (n = 6) for a hexagon we get the number of diagonals as 9. Similarly, substituting (n=5) for a pentagon we get the number of diagonals as 5.
The area of a hexagon with a given side of 20 is 1,039
The area of a hexagon with a given side of 20cm is 1039.2cm2
Parallelogram and a rectangle
Parallelogram and a rectangle
The total number of diagonals for a convex (or concave) polygon, a hexagon being of the former type, is given by the equation (n2 - 3n)/2, where n is the number of sides of the polygon. A hexagon has 6 sides, so plugging the number 6 into the above equation for n, one finds that a hexagon has: [62 - 3(6)]/2 = (36 - 18)/2 = 18/2 = 9 diagonals.
A rectangle would fit the given description
The number of diagonals in an n-sided polygon is given by nC2 - n (where n is the number of sides of the polygon) or in the expanded form: factorial (n) _______________________ {factorial (2) * factorial (n-2)} substituting (n = 6) for a hexagon we get the number of diagonals as 9. Similarly, substituting (n=5) for a pentagon we get the number of diagonals as 5.
There is no formula for a rectangle. There are formula for calculating its area, perimeter or length of diagonals from its sides, or it is possible to calculate the length of one pair of sides given the other sides and the area or perimeter, or the two lots of sides given area and perimeter and so on.
The area of a hexagon with a given side of 20 is 1,039
The area of a hexagon with a given side of 20cm is 1039.2cm2
The given vertices when plotted on the Cartesian plane forms a rectangle with diagonals of square root of 50 in lengths and they both intersect at (3.5, 4.5)
The Hexagon or in French, le Hexagon.
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.