L x B which gives the area of th rectangle then remaining we will have 4 equator triangle 1/3BH3 is the are for the triangle. cumulatively we will get area for the hexagan.
The total number of diagonals for a convex (or concave) polygon, a hexagon being of the former type, is given by the equation (n2 - 3n)/2, where n is the number of sides of the polygon. A hexagon has 6 sides, so plugging the number 6 into the above equation for n, one finds that a hexagon has: [62 - 3(6)]/2 = (36 - 18)/2 = 18/2 = 9 diagonals.
To find the area of the shaded region (the rectangle inside the hexagon), we first calculate the area of the hexagon using the formula ( \text{Area} = \frac{3\sqrt{3}}{2} \times a^2 ), where ( a ) is the apothem. Given that the apothem is 15.59 units, the area of the hexagon is approximately ( \frac{3\sqrt{3}}{2} \times (15.59^2) \approx 609.67 ) square units. Assuming the rectangle’s area is not specified, the shaded area would be the hexagon's area minus the rectangle's area. If the rectangle's area is provided, subtract it from the hexagon's area to find the shaded region's area.
A rectangle would fit the given description
The number of diagonals in an n-sided polygon is given by nC2 - n (where n is the number of sides of the polygon) or in the expanded form: factorial (n) _______________________ {factorial (2) * factorial (n-2)} substituting (n = 6) for a hexagon we get the number of diagonals as 9. Similarly, substituting (n=5) for a pentagon we get the number of diagonals as 5.
The area of a hexagon with a given side of 20 is 1,039
Parallelogram and a rectangle
Parallelogram and a rectangle
The total number of diagonals for a convex (or concave) polygon, a hexagon being of the former type, is given by the equation (n2 - 3n)/2, where n is the number of sides of the polygon. A hexagon has 6 sides, so plugging the number 6 into the above equation for n, one finds that a hexagon has: [62 - 3(6)]/2 = (36 - 18)/2 = 18/2 = 9 diagonals.
To find the area of the shaded region (the rectangle inside the hexagon), we first calculate the area of the hexagon using the formula ( \text{Area} = \frac{3\sqrt{3}}{2} \times a^2 ), where ( a ) is the apothem. Given that the apothem is 15.59 units, the area of the hexagon is approximately ( \frac{3\sqrt{3}}{2} \times (15.59^2) \approx 609.67 ) square units. Assuming the rectangle’s area is not specified, the shaded area would be the hexagon's area minus the rectangle's area. If the rectangle's area is provided, subtract it from the hexagon's area to find the shaded region's area.
A rectangle would fit the given description
The number of diagonals in an n-sided polygon is given by nC2 - n (where n is the number of sides of the polygon) or in the expanded form: factorial (n) _______________________ {factorial (2) * factorial (n-2)} substituting (n = 6) for a hexagon we get the number of diagonals as 9. Similarly, substituting (n=5) for a pentagon we get the number of diagonals as 5.
There is no formula for a rectangle. There are formula for calculating its area, perimeter or length of diagonals from its sides, or it is possible to calculate the length of one pair of sides given the other sides and the area or perimeter, or the two lots of sides given area and perimeter and so on.
The area of a hexagon with a given side of 20 is 1,039
The area of a hexagon with a given side of 20cm is 1039.2cm2
The Hexagon or in French, le Hexagon.
The given vertices when plotted on the Cartesian plane forms a rectangle with diagonals of square root of 50 in lengths and they both intersect at (3.5, 4.5)
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.