A regular pentagon with a radius (apothem) of 5.1 units cannot have sides of 7.5 units and, conversely, a regular pentagon with sides of length 7.5 units cannot have a radius of 5.1 units. The figure is, therefore, impossible.
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2
386.5
[ONLY WORKS FOR REGULAR PENTAGONS] I don't the exact formula, BUT, from what I learned in Geometry last year, I remember that if you have the radius from the center perpendicular to a side [for height] and if you have the length of the side of the pentagon, you can use a simple 1/2 times base time height to get 1/5th of the area. Then you just take that and multiply it by 5 to get the area of the whole pentagon. I know it looks complicated, but it's pretty simple: I have a REGULAR pentagon that I chop into 5 triangles I have the height = 2 I have the base [or the length of 1 side of the pentagon]= 4 1/2xbasexheight= 1/2x2x4= 4 So now you have the area of 1 triangle and multiply by 5 4x5= 20 your pentagon is 20 units squared. I hope this helped.
Multiply the known length by 5, because the sides are all the same length on a regular pentagon and a pentagon has 5 sides.
If you mean a pentagonal prism, then find the area of the pentagon 1st. Length of 1 side x 1.7, then multiply by the height of the prism. But I dont really know the regular Pentagon volume. sorry... hope you dont hate me for that.
If 6 is the side of a regular pentagon, the area is 61.937
== == The question does not make sense because the numbers are not consistent. It is a bit like asking the area of a circle if the radius is 6 and the diameter is 8. A circle's diameter is constrained to be twice the size of the radius. Similarly, the apothem of the specified pentagon is constrained to be a particular size and the apothem size is not 6.Also, a pentagon does not have a radius, so that part of the question does not make sense.Notes: * A previous version of the answer to this question on this site mentioned that the source of the solution is from www.icoachmath.com. However, there does not seem to be any pentagon area problems on that site. * A precise regular pentagon area is defined on the linked site:knol.google.com/k/scot-ellison/area-of-a-regular-pentagon
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2
What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
386.5
i belive it is 60
135
7
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
Area of a regular pentagon with a known side S can be closely approximated by formula 5S2/4 tan 36. Taking 4 tan 36 as 2.906 then the area sought is 2000/2.906 ie 688.23 sq units.
[ONLY WORKS FOR REGULAR PENTAGONS] I don't the exact formula, BUT, from what I learned in Geometry last year, I remember that if you have the radius from the center perpendicular to a side [for height] and if you have the length of the side of the pentagon, you can use a simple 1/2 times base time height to get 1/5th of the area. Then you just take that and multiply it by 5 to get the area of the whole pentagon. I know it looks complicated, but it's pretty simple: I have a REGULAR pentagon that I chop into 5 triangles I have the height = 2 I have the base [or the length of 1 side of the pentagon]= 4 1/2xbasexheight= 1/2x2x4= 4 So now you have the area of 1 triangle and multiply by 5 4x5= 20 your pentagon is 20 units squared. I hope this helped.
If a pentagon, which is a 5-sided figure, has 26.8 for a perimeter, then each side of that regular pentagon is 26.8 divided by 5 = 5.36 long. How do you get 26.8 for the perimeter of a regular pentagon? Use a regular pentagon with 5.36 for a side length.