135
124
That depends on the size of the pentagon, and whether it is regular or not. In general, you can divide the pentagon into three triangles, and calculate the area of each triangle separately.
i belive it is 60
True.
add all of the triangle area in a pentagon to get areaThe area A of a regular polygon with n sides each s units long, perimeter p, and apothem a:A = (ans)/2 or A = (ap)/2.
Area = 172.05 cm2
124
The area of a pentagon of side length t is given by the formula t2 (sqrt 25 + 10 (sqrt 5)) / 4, or 5t2 tan (54o) / 4. In this case, a pentagon with one side of 10cm has an area of 102 (sqrt 25 + 10 (sqrt 5)) / 4 = 172.05 cm2 (accurate to two decimal places).
The area of a regular pentagon with a radius of 7 is 10.1716. If the radius was 5, the area would be 7.26543.
If 6 is the side of a regular pentagon, the area is 61.937
There are 5 linear measures given. If that implies that the shape is a pentagon, there is no way to answer the question with out additional information about the angles in the pentagon. A triangle is the only polygonal shape whose area is uniquely determined by the length of its sides.
regular pentagon area of 12 000 m2 and an apothem of 40 m regular pentagon area of 12 000 m2 and an apothem of 40 m need to figure it out from area 12000 m2
That depends on the size of the pentagon, and whether it is regular or not. In general, you can divide the pentagon into three triangles, and calculate the area of each triangle separately.
21.4
Area = 440.44 sq feet
What is the area of a regular pentagon with side length of 9.4 feet and an apothem length of 6.5 feet
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).