-cos2(x)
1 = sin2(x) +cos2(x)
1 - cos2(x) = sin2(x)
-cos2(x) = sin2(x) - 1
COS squared Theta + SIN squared Theta = 1; where Theta is the angles measurement in degrees.
A Huge ASS
The minimum value of the parabola is at the point (-1/3, -4/3)
The height is a leg of a right triangle. The other leg is 1/2 of the side of the original triangle and the hypotenuse is a side of this same triangle. Use the Pythagorean theorem to solve for the height: If s is the length of the sides of the equilateral triangle, The height is the square root of s squared minus (s/2) squared. Since (s/2) squared is s squared over 4, s squared minus (s/2) squared is 3/4 s squared. I'll let you finish it off.
It can be found by: hypotenuse squared minus known side squared = unknown side squared
sin squared
Multiply both sides by sin(1-cos) and you lose the denominators and get (sin squared) minus 1+cos times 1-cos. Then multiply out (i.e. expand) 1+cos times 1-cos, which will of course give the difference of two squares: 1 - (cos squared). (because the cross terms cancel out.) (This is diff of 2 squares because 1 is the square of 1.) And so you get (sin squared) - (1 - (cos squared)) = (sin squared) + (cos squared) - 1. Then from basic trig we know that (sin squared) + (cos squared) = 1, so this is 0.
Sin squared, cos squared...you removed the x in the equation.
Sin squared is equal to 1 - cos squared.
No, unless "a" happens to be equal to 0, or to 1.
-1² = 1
2 sin2(x) + sin(x) - 1 = 0(2 sin + 1) (sin - 1) = 0Either 2 sin(x) + 1 = 02sin(x) = -1sin(x) = -0.5x = 210°, 330°or sin(x) - 1 = 0sin(x) = 1x = 90°
As X approaches infinity it approaches close as you like to 0. so, sin(-1/2)
2x squared minus 5x minus 3 factored is (2x+1)(x-3).
The answer is 1. sin^2 x cos^2/sin^2 x 1/cos^2 cos^2 will be cancelled =1 sin^2 also will be cancelled=1 1/1 = 1
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
(2x - 1)(4x + 1)