-cos2(x)
1 = sin2(x) +cos2(x)
1 - cos2(x) = sin2(x)
-cos2(x) = sin2(x) - 1
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COS squared Theta + SIN squared Theta = 1; where Theta is the angles measurement in degrees.
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The minimum value of the parabola is at the point (-1/3, -4/3)
The height is a leg of a right triangle. The other leg is 1/2 of the side of the original triangle and the hypotenuse is a side of this same triangle. Use the Pythagorean theorem to solve for the height: If s is the length of the sides of the equilateral triangle, The height is the square root of s squared minus (s/2) squared. Since (s/2) squared is s squared over 4, s squared minus (s/2) squared is 3/4 s squared. I'll let you finish it off.
It can be found by: hypotenuse squared minus known side squared = unknown side squared