The minute hand will be 4/12 = 1/3 of 360 degrees clockwise from up, so 120 degrees.
The hour hand will be 10/36 = 100 degrees clockwise from up.
120 - 100 = 20 degrees.
The angle between the two hands changes constantly at the rate of 5.5° per minute. This formula finds the angle between the two hands for a given time (h:m) taking the absolue value as shown: |5.5m - 30h| If the result is greater than 180°, subtract it from 360° to get the included angle.
At exactly 1 o'clock, the hour hand will be at an angle of 30 degrees, and the minute and second hands will be at an angle of 0 degrees.
If we simply imagine the minute hand is on the 6, and the hour hand is on the two, there will be a total of 120 degrees between the minute and the hour hand, 1/3 of the clock is covered between the two hands. However, it is not that simple. Because 30 minutes has travelled, the hour hand will be half way between the 2 and the 3. We know that every hour, the hour hand moves 30 degrees (360 / 12 hours = 30). Therefore, in 30 minutes, it will have travelled 15 degrees. Which means the hour hand is 15 degrees closer to the minute hand. Therefore, the actual angle between the minute and hour hand is actually 105 degrees.
18 times
105 degrees.A clock has 60 divisions around the outer edge representing the 60 minutes per hour. At 9.30 the minute hand will be at exactly 30 minutes. The hour hand will be exactly halfway between 9 hours and 10 hours (which is equal to 47.5 minutes according to the 60 minute divisions).As there are 60 divisions, and a circle is equal to 360 degrees, then each division is equal to 6 degrees.Therefore, the difference in minute divisions between the two hands = 47.5 - 30 = 17.5. The angle is therefore equal to 17.5 * 6 = 105 degrees.
It is 22.5 degrees.
360 times
360
The angle between the two hands changes constantly at the rate of 5.5° per minute. This formula finds the angle between the two hands for a given time (h:m) taking the absolue value as shown: |5.5m - 30h| If the result is greater than 180°, subtract it from 360° to get the included angle.
24
44. 22 in each 12 hour cyccle.
Lets start by thinking of a clock as a circle, with directly up being 0 degrees. At 12:00, both hands are at 0 pointing straight up. Every 60 minutes, the minute hand will make a complete revolution, so at any given time its angle is: minute_deg = minute * 360 / 60 = minute * 6; The hour hand will make a complete revolution every hour, so its formula is: hour_deg = hour * 360 / 12 = hour * 30; A function to find the angle would be: int angleBetweenHands(int hour, int minute) { if(hour > 12) // In case of 24 hour clock hour -= 12; int angle = hour * 30 - minute * 6; if(angle > 180) angle = 360 - angle; return(angle); }
The minute and hour hands form an angle of 60 degrees at 10 o'clock
24 times
minute_deg = minute * 360 / 60 = minute * 6;The hour hand will make a complete revolution every hour, so its formula is:hour_deg = hour * 360 / 12 = hour * 30;A function to find the angle would be:int angleBetweenHands(int hour, int minute){if(hour > 12) // In case of 24 hour clockhour -= 12;int angle = hour * 30 - minute * 6;if(angle > 180)angle = 360 - angle;return(angle);}Read more: C_code_to_find_angle_between_hour_hand_and_minute_hand
22215 pm is not a correct time, what time do you mean? The angle between the hands, if that is what you mean by 'the angle of the clock', does not depend on the length of the hands, so why have you given them? Please make the question clear and resubmit.
At exactly 1 o'clock, the hour hand will be at an angle of 30 degrees, and the minute and second hands will be at an angle of 0 degrees.