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Q: What is the angle formed by the hands of a clock at 9 20?

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Two 20 degree acute angles will be formed.

This problem can be solved as follows: The angle Ah of the hour hand of a clock, measured from the position at noon or midnight when the hour and minute hands exactly coincide, is Ah = (360 degrees/12 hours)th, where th is the time in hours, including fractions of hours, because the hour hand moves the entire 360 degrees around the clock in 12 hours. Similarly, the angle Am of the minute hand = (360 degrees/60 minutes)tm, where tm is the time in minutes only, including fractions of minutes. The stated time is 3 + 40/60 + 20/3600 hours = 3.672222... hours and the angle is therefore about 110. 11666666... degrees, using the formula above. The time in minutes only is 40 + 20/60 = 40.33333...., so that the angle of the minute hand is 242 degrees. The difference between them is therefore about 131.833..... degrees, or in fraction form 131 and 5/6.

An angle whose measure is 20 degrees!

180-20=160

Each exterior angle measures 20 degrees Each interior angle measures 160 degrees

Related questions

180o

On pages 20 and 21 Hint: They're not hands on your body their hands on a clock

20

20 degrees.

20 degrees

20 degree.

Two 20 degree acute angles will be formed.

A clock dial divides the full 360-degree circle into 12 hours, so hours are 360/12 = 30 degrees apart. At 9:20 the minute hand points to "4." With the hour hand pointing to "9" the hands are separated by 5 hours (or 7 for the outside angle), which is 5*30 = 150 degrees. The hour hand doesn't actually point to 9 at 9:20, however, having moved 20/60 minutes = 1/3 of an hour from 9 towards 10. If 1 hour is 30 degrees then 1/3 of an hour is 10 degrees. So the hands are 10 degrees farther apart, making the final answer 150 + 10 = 160 degrees.

If the little hand stayed on the 12, the angle would be 120°. Assuming both hands are pointing to 12 o'clock, when the big hand has moved to 20 past (1/3 of the way round) the little hand will have moved 1/3 of the way to the next number (1). So the angle between the hands will be: 1/3 × 360° - 1/3 × 1/12 × 360° = 120° - 10° = 110°.

20

On a non-military clock (civil, 12-hour) . . .-- The hour-hand is moving 360 degrees in 12 hours = 30 degrees per hour.3:20 is 31/3 hours past noon, so the hour-hand has moved 10/3 x 30 = 100 degrees.-- The minute-hand is moving 360 degrees per hour. So it starts at zero at thebeginning of each hour, and after 1/3 of the hour, it has moved 360/3 = 120 degrees.-- The angle between them at 3:20 is [ 120 - 100 ] = 20 degrees.

This problem can be solved as follows: The angle Ah of the hour hand of a clock, measured from the position at noon or midnight when the hour and minute hands exactly coincide, is Ah = (360 degrees/12 hours)th, where th is the time in hours, including fractions of hours, because the hour hand moves the entire 360 degrees around the clock in 12 hours. Similarly, the angle Am of the minute hand = (360 degrees/60 minutes)tm, where tm is the time in minutes only, including fractions of minutes. The stated time is 3 + 40/60 + 20/3600 hours = 3.672222... hours and the angle is therefore about 110. 11666666... degrees, using the formula above. The time in minutes only is 40 + 20/60 = 40.33333...., so that the angle of the minute hand is 242 degrees. The difference between them is therefore about 131.833..... degrees, or in fraction form 131 and 5/6.

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