It is: 72-lenghth of major arc = length of minor arc
Each arc of the circle will measure 360/5 = 72 degrees
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
It is 72 cm/8 = 9 cm.
The width is 6 cm and the length is 12 cm.
It is: 72-lenghth of major arc = length of minor arc
If this is a central angle, the 72/360 x (2xpix4) = 5.024
15 in
As you were copying the question, did you notice the drawing alongside it ? Well, see, that sketch is actually part of the question; anybody who wants to try and answer it needs to see that drawing.
Angular measure: 2*pi/5 radians or 72 degrees. or Length of arc: 2*r*pi/5 units or 144*r units, where r is the radius.
The arc represents 1/5 of the circumference (72 = 360/5) so the full circumference is 5 x 18.75 ie 93.75, which is 2 pi x the radius. The radius is therefore 46.875/pi, just over 14.9.
Goth
Any width and length whose product is 72 can outline 72 square feet. 8 × 9 = 72 square feet is one possibility.
72ºF = 22.2ºC
72
Oh, dude, a regular decagon has 10 sides, so each minor arc in the circle would be formed by connecting two consecutive vertices of the decagon. Since there are 10 vertices, there will be 10 minor arcs, each measuring 36 degrees. So, like, each minor arc would have a measure of 36 degrees. Easy peasy!
Length = 24 cm and width = 12 cm Check: 2*(24+12) = 72 cm