It is: 72-lenghth of major arc = length of minor arc
Each arc of the circle will measure 360/5 = 72 degrees
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
It is 72 cm/8 = 9 cm.
The width is 6 cm and the length is 12 cm.
It is: 72-lenghth of major arc = length of minor arc
If this is a central angle, the 72/360 x (2xpix4) = 5.024
15 in
As you were copying the question, did you notice the drawing alongside it ? Well, see, that sketch is actually part of the question; anybody who wants to try and answer it needs to see that drawing.
Angular measure: 2*pi/5 radians or 72 degrees. or Length of arc: 2*r*pi/5 units or 144*r units, where r is the radius.
The arc represents 1/5 of the circumference (72 = 360/5) so the full circumference is 5 x 18.75 ie 93.75, which is 2 pi x the radius. The radius is therefore 46.875/pi, just over 14.9.
Goth
Any width and length whose product is 72 can outline 72 square feet. 8 × 9 = 72 square feet is one possibility.
72ºF = 22.2ºC
72
Length = 24 cm and width = 12 cm Check: 2*(24+12) = 72 cm
Area = Length * Width so Width = Area / Length = 72 sq feet / 12 feet = 72/12 feet = 6 feet.