Find the area of a rhombs with diagonals that measure 8 and 10.
Area of the rhombus: 0.5*8*10 = 40 square feet
Area of a rhombus: base times perpendicular height Or area of a rhombus: 0.5 times product of its diagonals
54
If the diagonals of the rhombus are 13 and 15 then its area is 0.5*13*15 = 97.5 square units
Find the area of a rhombs with diagonals that measure 8 and 10.
Area of the rhombus: 0.5*8*10 = 40 square feet
The diagonals of a rhombus cannot be the same size.
The area of rhombus with diagonals 28Cm square and 28Cm is: 392 cm2
14*8 = 112 sq cm
If both diagonals are 10 units then the rhombus is, in fact, a square. Its area is 50 square units.
The answer depends on the measure of WHAT! Side length, angles, length of diagonals, area? And the answers to these depend on what information is given.
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
5680cm
Multiply the diagonals and divide by 2
Area of rhombus = 0.5 times the product of its diagonals