0
What else can I help you with?
What is the area of rhombus ABCD if AC 9 and BD 13?
58.5
What is the area of rhombus ABCD if AC equals 8 and BD equals 9?
A = (1/2)(ac)(bd) = (1/2)(8)(9) = 36
What is the area of rhombus ABCD if AC equals 12 and BD equals 7?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
In rhombus abcd bd equals 18 ac equals 24 what is the length of each side?
15 units
What is the perimeter of parallelogram abcd with ad equals 10 units ab equals 8 units ac equals 12 units ed equals 4.5 units?
If abcd is a parallelogram, then the lengths ab and ad are sufficient. The perimeter is 36 units.
What is the area of rhombus ABCD if AC 7 and BD 9?
31.5
What is the area of rhombus ABCD if AC 9 and BD 13?
58.5
What is the area of rhombus ABCD if AC 11 and BD 7?
38.5 Square units
What is the area of rhombus ABCD if AC equals 11 and BD equals 7?
38.5
What is the area of rhombus ABCD if AC equals 7 and BD equals 9?
31.5 square units
What is the area of rhombus ABCD if AC equals 9 and BD equals 13?
31.5 Square Units
What is the area of rhombus ABCD if AC equals 8 and BD equals 9?
A = (1/2)(ac)(bd) = (1/2)(8)(9) = 36
In rhombus ABCD BD 18 AC 24 What is the length of each side?
84
How may lines of symmetrey has a rhombus?
A rhombus has two lines of symmetry. They are also called its diagonals. Suppose there is a rhombus ABCD AC and BD are its lines of symmetry.
What is the area of rhombus ABCD AC 9 AND BD 13?
The area of a rhombus can be calculated using the formula: Area = (1/2) × d1 × d2, where d1 and d2 are the lengths of the diagonals. In this case, AC (d1) is 9 and BD (d2) is 13. Therefore, the area = (1/2) × 9 × 13 = 58.5 square units.
What is the area of rhombus ABCD if AC equals 12 and BD equals 7?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
In rhombus abcd bd equals 18 ac equals 24 what is the length of each side?
15 units
