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What do you do to find the surface area of a shape?
Rectangular Prisim 2x(area of front)+2x(area of side)+x2(area of length) Cube 2x(area of side)+2x(area of side)+2x(area of side)
What is the length of one side of this square 4x2 - 4xy plus y2?
4x2 - 4xy + y2 = (2x - y)2 so the length of the side of the square must be 2x-y.
What is a variable expression for the perimeter of the square with side 2x plus 1?
Perimeter of a square = 4 * sideP = 4 * (2x +1)P = 8x + 4
We are interested in the dimensions of a certain square. A rectangule has length twice the side of this square and width three less than theside If two areas are equal what are the square's dimension?
Area of square = x2Area of rectangle = 2x * (x-3)The two area are the same so x2 = 2x2 - 6xso x2 = 6xso x = 6The square has sides of length 6A+ = x2 = 2x2 - 6
The length of a rectangle is five feet more than twice its width and the area of the rectangle is sixty-three Find the dimensions of the rectangle?
Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.
