b * h / 2
The formula for area of triangle
22 * 4 cm = 88 cm
88 cm / 2 = 44 cm square
No, because there are infinitely many combinations of base and height which will lead to that result.
The base is 14Area = base x height, so base = area/height and 308/22 = 14
The area of a parallelogram that has a base 22 m and a height 4.5 m is 99m2
61. Divide the triangle down the middle, you have two right angled triangles with base 11 and height 60. Use pythagoras' theorem to get root(602+112) = 61.
There is no simple answer to the question. The information provided in the question is sufficient to determine that the base has an area of 41 square metres. But the shape of the base is indeterminate. It could be an equilateral triangle with a perimeter of 29.2 metres or a polygon with a very large number of sides and a perimeter of 22.7 metres. There are many intermediate solutions.
area of a triangle is half the base times the height .5*22*28=308
No. I can only find the height in terms of the base (and area) of the triangle, or the base in terms of the height (and area) of the triangle. Specifically, since: area = 1/2 x base x height ⇒ 22 = 1/2 x base x height ⇒ 44 = base x height I can rearrange that to: height = 44 ÷ base or base = 44 ÷ height For example, the triangle could have a base of 11 units and a height of 4 units; alternatively, the triangle could have a base of 10 units and a height of 4.4 units; or, the triangle could have a height of 2 units and a base of 22 units; etc.
132 according to siri
22
64.9 square feet probably.
Area = 0.5*4*11 = 22 square feet
No, because there are infinitely many combinations of base and height which will lead to that result.
The base is 14Area = base x height, so base = area/height and 308/22 = 14
the height has to be 22
A=1/2bh A=1/2x9x22 A=9x11 A=99 units2
It is 22 in2. Multiply 4 by 11 and divide by 2.
Not with certainty. Could be any two numbers whose product is 44. EG base 4, height 11 or base 2 height 22 or their reverses. This presupposes both are whole numbers, could be base 5½, height 8...