There is no simple answer to the question. The information provided in the question is sufficient to determine that the base has an area of 41 square metres. But the shape of the base is indeterminate. It could be an equilateral triangle with a perimeter of 29.2 metres or a polygon with a very large number of sides and a perimeter of 22.7 metres. There are many intermediate solutions.
Hdyf
It is 288 cm^2.
210 in 2
Find the surface area of each individual face and then add them together to give the total surface area of the pyramid.
The surface area is the area of the base plus the area of the slanted sides:SA = ba + lala = ps→SA = ba + ps
Yes. You can stack a regular pyramid.
LA=1/2ps
LA = 1/2psnewtest3
LA=1/2ps
Lateral Area=Perimeter of the base * height perimeter=20 height=6 so, Lateral Area=20 * 6 Lateral Area=120cm
False
Yes.
An isosceles trapezium.
Pyramid (regular) Lateral area : pl/2, where l = slant height : p = base perimeter Total area : pl/2+B where B = Base area.
SA=BA+LA SA=BA+1/2ps
It is 288 cm^2.
1/2(p)(sh) ~which means~ 1/2 x perimeter x slant height slant height= pathagorean theory= c squared= a squared+b squared
SA = BA + 1/2 ps SA = BA + LA