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There is no simple answer to the question. The information provided in the question is sufficient to determine that the base has an area of 41 square metres. But the shape of the base is indeterminate. It could be an equilateral triangle with a perimeter of 29.2 metres or a polygon with a very large number of sides and a perimeter of 22.7 metres. There are many intermediate solutions.

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Q: What is The regular pyramid below has a surface area of 63 square meters and a lateral area of 22 square meters. What is the perimeter of the base Round your answer to the nearest tenth of a meter.?
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Related questions

When p is the perimeter of the base and s the slant height of a regular pyramid What is a valid formula for the lateral area?

LA=1/2ps


What would be the formula for the lateral area of a regular pyramid where the base is a square with perimeter p and s is the slant height?

LA = 1/2psnewtest3


Let p be the perimeter of the base and s the slant height of a regular pyramid What is a valid formula for the lateral area?

LA=1/2ps


What is the lateral area of a regular quadrangular prism that has a perimeter of 20 cm and a height of 6 cm?

Lateral Area=Perimeter of the base * height perimeter=20 height=6 so, Lateral Area=20 * 6 Lateral Area=120cm


In the equation for the lateral area of a regular pyramid one can replace the slant height with the altitude of the pyramid?

False


Can a regular square pyramid have base 12 and lateral edge 29?

Yes.


What is the shape of one lateral face of a frustum of a regular pyramid?

An isosceles trapezium.


How do you calculate the area of a pyrmid?

Pyramid (regular) Lateral area : pl/2, where l = slant height : p = base perimeter Total area : pl/2+B where B = Base area.


Consider a regular pyramid where p is the perimeter of the base s is the slant height BA is the base area and LA is the lateral area What is a valid formula for the surface area?

SA=BA+LA SA=BA+1/2ps


What is the surface area of a regular triangular pyramid with the lateral surface area of 72cm?

It is 288 cm^2.


How do you find lateral area of a regular square pyramid?

1/2(p)(sh) ~which means~ 1/2 x perimeter x slant height slant height= pathagorean theory= c squared= a squared+b squared


Which formulas can be used to find the surface area of a regular pyramid where p is the perimeter of the base s is the slant height BA is the base area and LA is the lateral area?

SA = BA + 1/2 ps SA = BA + LA