Q: What is the area of rhombus DEFG if DF is 10 and EF is 11?

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11

38.5 Square units

Area of the trapezoid: 0.5*(8+11)*10 = 95 square measurements

Let the sides be abc and their opposite angles be ABC Angle C: (10^2 +11^2 -15^2)/(2*10*11) = 91.04179885 degrees Area: 0.5*10*11*sin(91.04179885) = 54.99090834 Area to the nearest integer = 55 square cm

To find the area of 11 and 18 you multiply it.

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If 10 and 11 are its diagonals then its area is: 0.5*10*11 = 55 square units

The diagonals of a rhombus are perpendicular to each other and bisect one another. So you can consider the diagonals dividing the rhombus into 4 identical, right-angled triangles where the sides subtending the right angle are of length 10/2 and 11/2. The area of each of these triangles is 1/2 * 10/2 * 11/2 = 110/8 There are 4 such triangles, so their combined area is 4 * 110 / 8 = 110 / 2 = 55 square units.

11

38.5 Square units

38.5

The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonalsIn your case, that's 14 x 17 / 2 = 119

Area of the trapezoid: 0.5*(8+11)*10 = 95 square measurements

we know that area of rect= l* b area = 11* 10 =110 cm^2

Let the sides be abc and their opposite angles be ABC Angle C: (10^2 +11^2 -15^2)/(2*10*11) = 91.04179885 degrees Area: 0.5*10*11*sin(91.04179885) = 54.99090834 Area to the nearest integer = 55 square cm

The formula for the area of a triangle is (base x height)/2. Since we're dealing with a right triangle, we can say that the base and height are 10 and 11 units long, respectively. Therefore, the are is (10 x 11)/2 or 55 units squared.

If the side is 11 then the perimeter is 44.The altitude is irrelevant. It can be anything less than 11, with no effect on the perimeter.

The area is approximately 22.91 units2