The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals
In your case, that's 14 x 17 / 2 = 119
112
Well, the area of a rhombus is 1/2*d(1)*d(2). 1/2 * 8 * 14 is 56, so the area of this rhombus is 56 square cm.
56 cm squared
An angle is not normally defined by two characters. Also, a rhombus cannot have two angles whose measures are 14 and 17: any two angles MUST be complementary or equal.
29
The area is 56 cm2
A rhombus has four equal sides and its diagonals bisect each other at right angles. The area of the rhombus ia given by following formula where x and y are the lengths of the diagonals of the rhombus...A=1/2xy. Example, the diagonals of a rhombus where x = 26 and y = 14....A=1/2xy...=1/2 x 26 x 14 which equals 182. so the area of the rhombus is 182 square inches, miles or whatever measurement you are dealing with the 3d annaloge to a rhombus is the rhomboid, the formula to fin dteh volume of that is A . (B x C).
Its area is: 0.5*10*14 = 70 square feet
To find the area of a rhombus, you can use the formula: Area = (d1 * d2) / 2, where d1 and d2 are the lengths of the diagonals. In this case, the diagonals AC and DB are 14 cm and 8 cm, respectively. Plugging in these values, the area is (14 cm * 8 cm) / 2 = 56 cm². Thus, the area of the rhombus is 56 cm².
x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?
x/14 = -11x = -11*14-154
14*8 = 112 sq cm