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The diagonals of a rhombus are perpendicular to each other and bisect one another. So you can consider the diagonals dividing the rhombus into 4 identical, right-angled triangles where the sides subtending the right angle are of length 10/2 and 11/2. The area of each of these triangles is 1/2 * 10/2 * 11/2 = 110/8 There are 4 such triangles, so their combined area is 4 * 110 / 8 = 110 / 2 = 55 square units.

Q: What is the area of rhombus DEFG if DF equals 10 and EG equals 11?

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60 square units.

Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40

130 is the area.

If this is a rhombus then the area is half the product of the diagonals - 10 x 14 = 140. Half of 140 = 70, so the area is 70 square feet.

If you have a rhombus that has been divided into four in this way, each part has an equal area. Each part is also a right-angled triangle, whose perpendicular sides are of lengths 5 and 6 inches (since these will be half the distances of the diagonals of the rhombus). Draw a sketch and you will see that this is the case. The area of a right-angled triangle is given by: A = base x height / 2 = 5 inches x 6 inches / 2 = 15 square inches Since there are four of these triangles, each having an area of 15 square inches, the total area of the rhombus is given by: A = 4 x 15 square inches = 60 square inches

Related questions

If 10 and 11 are its diagonals then its area is: 0.5*10*11 = 55 square units

If those are its diagonals then area is: 0.5*10*11 = 55 square units other wise use Pythagoras to find diagonal EG because area of a rhombus is 0.5 times the product of its diagonals.

If both diagonals are 10 units then the rhombus is, in fact, a square. Its area is 50 square units.

Area of the rhombus: 0.5*8*10 = 40 square feet

10

The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.

60 square units.

Area of a rhombus= 1/2 (d₁) (d₂); where, d₁ and d₂ are the diagonals. Solution: A=1/2 (10) (12) = 60 feet²

Find the area of a rhombs with diagonals that measure 8 and 10.

Its area is: 0.5*10*14 = 70 square feet

60 feet

With perimeter 10 and all sides equal fora rhombus, each side (base) is 10/4 = 2.5 inch Area = base times altitude = 2.5 x 12 = 30