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The diagonals of a rhombus are perpendicular to each other and bisect one another. So you can consider the diagonals dividing the rhombus into 4 identical, right-angled triangles where the sides subtending the right angle are of length 10/2 and 11/2. The area of each of these triangles is 1/2 * 10/2 * 11/2 = 110/8 There are 4 such triangles, so their combined area is 4 * 110 / 8 = 110 / 2 = 55 square units.

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Q: What is the area of rhombus DEFG if DF equals 10 and EG equals 11?
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Related questions

What is the area of rhombus DEFG if DF10 and EG11?

If 10 and 11 are its diagonals then its area is: 0.5*10*11 = 55 square units


What is the area of rhombus DEFG if DF is 10 and EF is 11?

If those are its diagonals then area is: 0.5*10*11 = 55 square units other wise use Pythagoras to find diagonal EG because area of a rhombus is 0.5 times the product of its diagonals.


What is the area of a rhombus with diagonals of 10?

If both diagonals are 10 units then the rhombus is, in fact, a square. Its area is 50 square units.


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The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.


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