If: x^2 +y^2 = 12x -10y -12 Then: x^2 +y^2 -12x +10y +12 = 0 Completing the squares: (x-6)^2 +(y+5)^2 = 49 which is the radius squared Center of circle: (6, -5) Diameter of circle: 14 units
well it means that if u square something that's is all i know
Equation: x^2 + y^2 +10x -14y +10 = 0 Completing the squares: (x+5)^2 + (y-7) -25-49 +10 = 0 So: (x+5)^2 + (y-7) = 64 Therfore the circle's centre is at (-5, 7) and its radius is 8
Equation of circle: x^2 +y^2 +6x +10y -2 = 0 Completing the squares: (x+3)^2 +(y+5)^2 = 36 Radius of circle: 6 Center of circle: (-3, -5) Distance from (-2, 3) to (-3, -5) is sq rt of 65 which is hypotenuse of a right triangle Using Pythagoras' theorem: square root of 65^2 -6^2 = 29 Therefore length of tangent line is the square root of 29 Note that the tangent line of any circle always meets its radius at right angles which is 90 degrees.
The distance around any object is called its perimeter. The perimeter of a circle has a specific formula: 2(pi)r where pi is a number that is approximately 3.14 and r represents the circle's radius. In this case we are given the circle's diameter, however remember that the diameter of a circle equals two times its radius. So if: d = 50' and d = 2r Then r = 25' Now plus this radius into or equation to get: 2(3.14)(25) = 157' To get the distance around this circle 8 times, multiply the perimeter by 8: 157' * 8 = 1,256 feet
That's the equation of a circle with its center at the origin and a radius of 8.
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
Centre = (0,0), the origin; radius = 11
Draw a circle with its center at the origin and a radius of 3.
It is the equation of a circle with radius of 6 and its center at the origin.
The centre is (3,-1) and the radius is sqrt(10).
Radius = 1111
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
The radius will depend on the plus or minus value of 10 or whether or not it needs a plus sign but the center of the circle is at (-2, 3)
x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5
If that equals 16 then the radius is 4
4