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Q: What is the center and the radius of the circle x2 plus y2 -4x -6y -3 equals 0?

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Centre = (-9, -5)Radius = 8

3x² + 3y² = 75

Centre of circle: (4, -2) Slope of tangent: 1 Slope of radius: -1 Radius equation: y--2 = -1(x-4) => y = -x+2

well it means that if u square something that's is all i know

10. Equation of circle is x2 + y2 = r2. Consider: when x = 0 y2 must = 100 so y = 10 which describes a circle centre the origin, radius 10. Similarly when x = 10 y must be 0.

Related questions

That's the equation of a circle with its center at the origin and a radius of 8.

The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1

Centre = (0,0), the origin; radius = 11

Draw a circle with its center at the origin and a radius of 3.

It is the equation of a circle with radius of 6 and its center at the origin.

Radius = 1111

The centre is (3,-1) and the radius is sqrt(10).

Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..

The radius will depend on the plus or minus value of 10 or whether or not it needs a plus sign but the center of the circle is at (-2, 3)

If that equals 16 then the radius is 4

4

x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5

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