Equation of circle: x^2 +y^2 -4x -6y -3 = 0
Completing the squares: (x-2)^2 +(y-3)^2 = 16 square units
Therefore center of circle is at (2, 3) and its radius is 4 units
Centre = (-9, -5)Radius = 8
3x² + 3y² = 75
Centre of circle: (4, -2) Slope of tangent: 1 Slope of radius: -1 Radius equation: y--2 = -1(x-4) => y = -x+2
well it means that if u square something that's is all i know
10. Equation of circle is x2 + y2 = r2. Consider: when x = 0 y2 must = 100 so y = 10 which describes a circle centre the origin, radius 10. Similarly when x = 10 y must be 0.
That's the equation of a circle with its center at the origin and a radius of 8.
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
Centre = (0,0), the origin; radius = 11
Draw a circle with its center at the origin and a radius of 3.
It is the equation of a circle with radius of 6 and its center at the origin.
Radius = 1111
The centre is (3,-1) and the radius is sqrt(10).
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
The radius will depend on the plus or minus value of 10 or whether or not it needs a plus sign but the center of the circle is at (-2, 3)
If that equals 16 then the radius is 4
4
x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5