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Equation of circle: x^2 +y^2 -4x -6y -3 = 0

Completing the squares: (x-2)^2 +(y-3)^2 = 16 square units

Therefore center of circle is at (2, 3) and its radius is 4 units

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βˆ™ 6y ago
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βˆ™ 6y ago

Centre = (2, 3)Radius = 4.

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Q: What is the center and the radius of the circle x2 plus y2 -4x -6y -3 equals 0?
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