It is the square root of (6-8)^2+(2-10)^2 = 2 times sq rt of 17 which is about 8.246 rounded to 3 decimal place
The distance is the square root of 125 (which is about 11.18) 1 to -9 = 10 units -2 to 3 = 5 units distance = sqrt (102 + 52) = sqrt (125)
The distance between (4, 5) and (10, 3) = sqrt(40) = 2*sqrt(10) = 6.3246 approx.
The disadvantages of four figure grid references are 1 grid reference is 10 2 is 10 3 is 30 and 4 goes to 400..
If you mean points of: (-6, -10) and (2, 5) then it works out as 17
The distance is about 42.06.X distance 20, Y distance 37202 + 372 = L2L = sqrt (400 +1369)L = 42.0595
The distance is the square root of 125 (which is about 11.18) 1 to -9 = 10 units -2 to 3 = 5 units distance = sqrt (102 + 52) = sqrt (125)
If you mean (4, 5) and (10, 13) then the distance is 10
10 units
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
Approximately 11.18 That would give a change of -10 in the x direction and +5 in the y direction. Using the Pythagorean theorem, the distance between the two points would be the square root of 125 or approximately 11.18
The distance between (4, 5) and (10, 3) = sqrt(40) = 2*sqrt(10) = 6.3246 approx.
If you mean points of (5, 5) and (1, 5) then the distance is 4
The distance along a straight line is 10. Using the Pythagorean equation, c2 = a2 + b2 where the x change is 6 and the y change is 8, c2 = 62 + 82 = 36 + 64 = 100 c = [sqrt 100] = 10
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
idk look it u instead of wasting 10 minutes of ur life typing the question onto this website
(12, 4) and (12, - 10)Distance = sqrt[(Y2 - Y1)2 + (X2 - X1)2]Distance = sqrt[(- 10 - 12)2 + (12 - 12)2]Distance = sqrt(- 22)2Distance = 22==============Could be...(0, 22) as I am not sure here.
If the grid is 10 by 10 or 100 squares, then 2/10 would be 20 squares.