If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
what is the distance between the points (-3, -3) and (6, -1)
Points: (-3, -4) and (-8, 1) Distance: square root of 50 or about 7.071 to three decimal places
If you mean points of (1, -2) and (-9, 3) then it works out as about 11
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
The distance between the points is two times the square root of 3.
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
7.2111 (rounded)
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
1
If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
what is the distance between the points (-3, -3) and (6, -1)
(-3-5)2+(-1--1)2 = 64 and the square root of this is the distance which is 8