Use the standard slope/intercept equation for a straight line and substitute the figures given in the question.
y = mx + c .......m is the slope so we can now write y = -5x + c
Substituting the ordered pair for x and y gives : 2 = (-5*0) + c = c
The final equation is therefore, y = -5x + 2
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
y = 7
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
The equation works out as: y = 5x+7
The equation is x = -7.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
33
Point: (1, 4) Slope: -3 Equation: y = -3x+7
Point: (2, 17)Slope: 7Equation: y = 2x+13
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
If you mean a point of: (-4, 7) and a slope of 4 Then the equation works out as: y = 4x+23
The equation is: y = 4x-22
Slope=8 point=(-7,3)
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
y = 5
y = 7