It is: (x-3)^2 +(y -2)^2 = 18.49
We have to guess at what the question means where it says a "32 foot circle".-- Is the circle 32 feet in diameter . . . across the widest part ?-- Is it 32 feet in radius . . . from the center to the curve ??-- Is it 32 feet in circumference . . . around the curve ???We'll assume it's 32 feet in "diameter" ... across the 'widest' part.The area of a circle is [ pi R2 ] where 'R' = the radius = 1/2 of the diameter.pi R2 = pi (32/2)2 = pi (16)2 = 256 pi = 804.25 square feet (rounded)
32"
It is 64 inches.
32 pi = 100.531 (rounded)
Divide that by (2 x pi).
A circle with a radius of 32 inches has an area of 3,216.99 square inches.
radius = 32/(2*pi) inches
The radius is 32 because the height of the hemisphere (which is half of a sphere) is the same thing as the radius (which is half the length of the diameter); the radius is the distance from the center to any point on the edge or surface of the circle/sphere.
A circle with a radius of 32 cm has a circumference of 201.06 cm.
201.06 in
The equation of the circle with center (h, k) and radius r is of the form(x - h)2 + (y - k)2 = r2x2 + y2 - 10x + 6y = 47 (complete the square)[x2 - 10x + (10/2)2] + [y2 + 6y +(6/2)2] = 47 + (10/2)2 +(6/2)2(x2 - 10x + 52) + (y2 + 6y + 32) = 47 + 52 + 32(x - 5)2 + (y + 3)2 = 81(x - 5)2 + (y + 3)2 = 92So that the center of the circle is (5, -3) and the radius is 9.
A circle with a radius of 16 inches (32/2) has a circumference of 100.53 inches.
There need to be squares in there for x and y - I think you're asking for the centre of the circle with equation: (x + 5)2 + (y - 3)2 = 56 in which case the centre is (-5, 3) A circle with centre (xo, yo) and radius r has equation of the form: (x - xo)2 + (y - yo)2 = r2
32
A circle in which the distance from its centre to its boundary is 32 inches.
The area of any circle is (pi) x (radius)2 .The radius is 1/2 of the diameter.
The radius of a circle is half the length of the diameter, so if the diameter is 32 centimeters the radius is 16 centimeters.