Point of passage (6, 2) and a slope of 53
Equation: y-2 = 53(x-6) => y = 53x-316
It is y = 53x - 316.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
The equation works out as: y = 5x+7
y = 7
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
The equation is x = -7.
y = 2x + 1.
sda
Assuming the point is (9, -4), the equation is y = -4.
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
The equation is: y = 4x-22
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
414
The equation works out as: y = 5x+7
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
"14" is not a point; you need two coordinates to specify a point.
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10