If the polygon has n sides, the sum of the interior angles is (n - 2)*180 degrees. So (n - 2)*180 = 8460 (n - 2) = 8460/180 = 48 So n = 48 + 2 = 50 sides.
It has (8280+360)/180 = 48 sides
If all the interior angles add up to 8280 degrees then the polygon will have 48 sides.
48 sides A formula for finding the number of sides of a regular polygon given an interior angle: 360/(180-angle)=sides
To find the sum of the angles for any polygon just use this formula: (n-2) times 180 where n is the number of sides in the polygon. So for a 48-gon it would be : (48 - 2) times 180 46 times 180 = 8280 degrees
If the polygon has n sides, the sum of the interior angles is (n - 2)*180 degrees. So (n - 2)*180 = 8460 (n - 2) = 8460/180 = 48 So n = 48 + 2 = 50 sides.
A polygon with n sides inscribed in a circle has an angle sum of 180xn-360 So the problem is find n so that 180n-360=9000 => n=48 The regular polygon with an angle sum of 9000 has 48 sides
It has (8280+360)/180 = 48 sides
If all the interior angles add up to 8280 degrees then the polygon will have 48 sides.
if you mean the sum of the interior angles, then it is 8640. the formula you use to find the sum of the interior angles of a polygon is (n-2)180, n being the number of sides. in this problem, you would plug in 50 for n, so 50-2=48, and 48x180=8640.
48 sides A formula for finding the number of sides of a regular polygon given an interior angle: 360/(180-angle)=sides
The interior angles of a 48 sided polygon add up to 8280 degrees
It is a 48 sided polygon whose interior angles add up to 8280 degrees
It is a 48 sided polygon whose interior angles add up to 8280 degrees
Sum of Interior Angles = (n-2)180 8280/180 = n-2 46 = n-2 48 = n
The sum of the interior angles of a polygon can be found using the formula: (n-2) × 180° Therefore, the interior angles of a pentacontagon; a fifty-sided polygon, will add up to: (50-2) × 180° (48) × 180° 8640°
Exterior angles are 7.5 There are 48 sides.