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The interior angles of a 48 sided polygon add up to 8280 degrees
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∙ 12y ago
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How many sides if the sum of the interior angles of a polygon is 8460?
If the polygon has n sides, the sum of the interior angles is (n - 2)*180 degrees. So (n - 2)*180 = 8460 (n - 2) = 8460/180 = 48 So n = 48 + 2 = 50 sides.
The some of the interior angles of a polygon is 8280. how many sides does the polygon have?
It has (8280+360)/180 = 48 sides
How many sides does polygon have if the interior angle measures 8280?
If all the interior angles add up to 8280 degrees then the polygon will have 48 sides.
How many sides are in a regular polygon with an interior angle of 172.5?
48 sides A formula for finding the number of sides of a regular polygon given an interior angle: 360/(180-angle)=sides
What is the sum of the interiorangles of a 48-gon?
To find the sum of the angles for any polygon just use this formula: (n-2) times 180 where n is the number of sides in the polygon. So for a 48-gon it would be : (48 - 2) times 180 46 times 180 = 8280 degrees
How many sides if the sum of the interior angles of a polygon is 8460?
If the polygon has n sides, the sum of the interior angles is (n - 2)*180 degrees. So (n - 2)*180 = 8460 (n - 2) = 8460/180 = 48 So n = 48 + 2 = 50 sides.
Is there a regular polygon with an interior angle sum 9000?
A polygon with n sides inscribed in a circle has an angle sum of 180xn-360 So the problem is find n so that 180n-360=9000 => n=48 The regular polygon with an angle sum of 9000 has 48 sides
The some of the interior angles of a polygon is 8280. how many sides does the polygon have?
It has (8280+360)/180 = 48 sides
How many sides does polygon have if the interior angle measures 8280?
If all the interior angles add up to 8280 degrees then the polygon will have 48 sides.
What is the sum of a fifty sided polygon?
if you mean the sum of the interior angles, then it is 8640. the formula you use to find the sum of the interior angles of a polygon is (n-2)180, n being the number of sides. in this problem, you would plug in 50 for n, so 50-2=48, and 48x180=8640.
How many sides are in a regular polygon with an interior angle of 172.5?
48 sides A formula for finding the number of sides of a regular polygon given an interior angle: 360/(180-angle)=sides
What is the sum of interior angles in a tetracontakaioctagon?
The interior angles of a 48 sided polygon add up to 8280 degrees
What is the sum of the interior angles of a tetracontakaioctagon?
It is a 48 sided polygon whose interior angles add up to 8280 degrees
What is the sum of interior angles of a tetracontakaioctagon?
It is a 48 sided polygon whose interior angles add up to 8280 degrees
How many sides would a polygon if the measure of the interior angles is 8280 degrees?
Sum of Interior Angles = (n-2)180 8280/180 = n-2 46 = n-2 48 = n
What is the sum of the interior angles Pentacontagon?
The sum of the interior angles of a polygon can be found using the formula: (n-2) × 180° Therefore, the interior angles of a pentacontagon; a fifty-sided polygon, will add up to: (50-2) × 180° (48) × 180° 8640°
What size are exterior angles on a regular polygon have if each interior angle is 172.5 and how many sides does it have?
Exterior angles are 7.5 There are 48 sides.
