100 Feet...
pathway is bisecting the rectangle into 2 right-angled triangles. Length of the hypotenuse is the length of pathway
The diagonal length of a rectangular solid can be calculated using the formula ( d = \sqrt{l^2 + w^2 + h^2} ), where ( l ), ( w ), and ( h ) are the length, width, and height of the solid, respectively. This formula derives from the Pythagorean theorem applied in three dimensions. The diagonal represents the longest straight line that can be drawn between two opposite corners of the solid.
Using Pythagoras' theorem the length of the diagonal is 15 units
If you know the lengths of the four sides that make up the rectangle (I assume this question is referring to a rectangular object) you can use the pythagorean theorem (a^2 + b^2 = c^2) to solve for the length of the diagonal which is represented in the formula by the letter c.
The length of the other diagonal works out as 12cm
Using Pythagoras its length is 26.833 units rounded to 3 dp
The diagonal length of a rectangular solid can be calculated using the formula ( d = \sqrt{l^2 + w^2 + h^2} ), where ( l ), ( w ), and ( h ) are the length, width, and height of the solid, respectively. This formula derives from the Pythagorean theorem applied in three dimensions. The diagonal represents the longest straight line that can be drawn between two opposite corners of the solid.
If the sides of a rectangle (not rectangular) are X and Y units, then the corner to corner length - the diagonal - is sqrt(X2 + Y2)
Using Pythagoras' theorem the length of the diagonal is 15 units
The length of the diagonal (not diognal), is sqrt(Length^2 + Breadth^2 + Height^2).
Use Pythagoras' theorem to find the length of the diagonal of a rectangle.
13 ft
draw a straight line from one corner to its opposite corner the length of the diagonal is the length of one side times the square root of 2
Diagonal = sqrt(36 + 25) ie sqrt 61 which is 7.8 inchesto the nearest tenth.
To find the length of the diagonal of a rectangular book, you can use the Pythagorean theorem. The formula is (d = \sqrt{l^2 + w^2}), where (l) is the length and (w) is the width. Substituting the given values, (d = \sqrt{6^2 + 5^2} = \sqrt{36 + 25} = \sqrt{61}). Therefore, the length of the diagonal is approximately 7.81 inches.
(202 + 152)0.5 = 25"
68m
This question could be answered if only it had also given either the width or the diagonal of the park.Knowing only the length of the park, the jogging loop could still be anything at all.Maybe there's some rule that relates the width of a rectangular city park to its length. We don't know it.