100 Feet...
pathway is bisecting the rectangle into 2 right-angled triangles. Length of the hypotenuse is the length of pathway
Using Pythagoras' theorem the length of the diagonal is 15 units
The diagonal line of a rectangle for example is greater than its length.
The length of the other diagonal works out as 12cm
If you know the lengths of the four sides that make up the rectangle (I assume this question is referring to a rectangular object) you can use the pythagorean theorem (a^2 + b^2 = c^2) to solve for the length of the diagonal which is represented in the formula by the letter c.
Using Pythagoras its length is 26.833 units rounded to 3 dp
If the sides of a rectangle (not rectangular) are X and Y units, then the corner to corner length - the diagonal - is sqrt(X2 + Y2)
Using Pythagoras' theorem the length of the diagonal is 15 units
The length of the diagonal (not diognal), is sqrt(Length^2 + Breadth^2 + Height^2).
The diagonal line of a rectangle for example is greater than its length.
Use Pythagoras' theorem to find the length of the diagonal of a rectangle.
13 ft
draw a straight line from one corner to its opposite corner the length of the diagonal is the length of one side times the square root of 2
Diagonal = sqrt(36 + 25) ie sqrt 61 which is 7.8 inchesto the nearest tenth.
(202 + 152)0.5 = 25"
68m
This question could be answered if only it had also given either the width or the diagonal of the park.Knowing only the length of the park, the jogging loop could still be anything at all.Maybe there's some rule that relates the width of a rectangular city park to its length. We don't know it.
The diagonal is SQUAREROOT(1022 + 2962) = 313.08ft Angle = tan-1(102/296) = 19.01 degrees