FG should be 12.2²-12²(half of 24)=4.84 then square root it which equals 2.2 and then you double it so the answer is 4.4
The diagonal is approximately 38.42 feet.
Using Pythagoras' theorem the diagonal works out as 51 inches
Using Pythagoras' theorem it is 26 inches in length
That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.
The diagonal of a 12' x 24' rectangle is approx 26.8'.
FG should be 12.2²-12²(half of 24)=4.84 then square root it which equals 2.2 and then you double it so the answer is 4.4
The diagonal is about 28.3 feet.
The diagonal is approximately 38.42 feet.
Using Pythagoras' theorem the diagonal works out as 51 inches
If it's a rectangle and you know its length and height then use Pythagoras' theorem to find the length of its diagonal
The average length would be 24' but bigger is always better.
The perimeter of a square with a diagonal length of 24 square root 2 millimeters (33.94 mm) is: 96 mm
Using Pythagoras' theorem it is 26 inches in length
Ah, what a lovely question! To find the diagonal measurement of a square, we can use the Pythagorean theorem. So, for a square that is 24 feet by 24 feet, we can use the formula diagonal = √(side length squared + side length squared). Plugging in the values, we get diagonal = √(24^2 + 24^2) = √(576 + 576) = √1152 ≈ 33.94 feet.
That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13