Using Pythagoras its length is 26.833 units rounded to 3 dp
FG should be 12.2²-12²(half of 24)=4.84 then square root it which equals 2.2 and then you double it so the answer is 4.4
The diagonal is approximately 38.42 feet.
Using Pythagoras' theorem the diagonal works out as 51 inches
Using Pythagoras' theorem it is 26 inches in length
That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.
The diagonal of a 12' x 24' rectangle is approx 26.8'.
FG should be 12.2²-12²(half of 24)=4.84 then square root it which equals 2.2 and then you double it so the answer is 4.4
The diagonal is about 28.3 feet.
The diagonal is approximately 38.42 feet.
Using Pythagoras' theorem the diagonal works out as 51 inches
If it's a rectangle and you know its length and height then use Pythagoras' theorem to find the length of its diagonal
The average length would be 24' but bigger is always better.
The perimeter of a square with a diagonal length of 24 square root 2 millimeters (33.94 mm) is: 96 mm
Using Pythagoras' theorem it is 26 inches in length
Diagonal = 24*sqrt(2) = 34 units, approx.Diagonal = 24*sqrt(2) = 34 units, approx.Diagonal = 24*sqrt(2) = 34 units, approx.Diagonal = 24*sqrt(2) = 34 units, approx.
Oh, dude, you're hitting me with some geometry now. So, like, the diagonal of a square is the hypotenuse of a right triangle formed by two sides of the square, right? Using the Pythagorean theorem, you can calculate it as the square root of (24^2 + 24^2), which simplifies to 24√2 feet. So, like, the diagonal of a 24 feet x 24 feet square is 24√2 feet.
That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.