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Doesn't seem likely, does it? A diagonal 50 times the length of the sides?

Diagonal = sqrt(252 + 252), ie sqrt 1250(!) which is 35.36 to the nearest hundredth.

Q: If you use the Pythagorean theorem to find the length of a diagonal in a square and all sides are 25m would the answer be 1250m?

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Not always, the diagonal can be figured out using the Pythagorean Theorem (a²+b²=c²). Where the diagonal is the hypotenuse (c). By rearranging the Pythagorean Theorem, you can see that the diagonal of a square is always 1.4 times the side of the square.

d=x√2 where d is a diagonal and x is a side d=80√2 (or 113.137)

By the Pythagorean Theorem, it's simply L*Sqrt(2), where L is the length of the side, and Sqrt denotes the square root.

diagonal="c" side=9="9"="9" sincec^2=b^2+a^2, diagonal=square root of(2(9^2))=

Use Pythagoras' theorem to find the length of the diagonal in the square

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Not always, the diagonal can be figured out using the Pythagorean Theorem (a²+b²=c²). Where the diagonal is the hypotenuse (c). By rearranging the Pythagorean Theorem, you can see that the diagonal of a square is always 1.4 times the side of the square.

The diameter of the circle is congruent to the length of the diagonal of the inside square. If you know the length of one side of the square, you can use pythagorean's theorem to solve for its diagonal (hypotenuse) and thusly the square's diameter.

Each side of the square is 20 inches and by using Pythagoras' theorem its diagonal is 20 times the square root of 2 which is about 28.284 inches rounded to 3 decimal places.

Squares do not have diameters; circles have them. If you are referring to the diagonal of a square, then you would use Pythagorean's Theorem to determine the length of the diagonal. 'Square' the length of one side and multiply by 2, then take the square root of that number to get the length of the diagonal. that is = under root( 2 s) where s= side

d=x√2 where d is a diagonal and x is a side d=80√2 (or 113.137)

By the Pythagorean Theorem, it's simply L*Sqrt(2), where L is the length of the side, and Sqrt denotes the square root.

diagonal="c" side=9="9"="9" sincec^2=b^2+a^2, diagonal=square root of(2(9^2))=

Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.

25 feet Pythagorean theorem says length of diagonal is square root of (width squared plus length squared). This is a 3-4-5 ratio right triangle

length2+width2 = diagonal2 and the square root of this is the size of the diagonal

Use Pythagoras' theorem to find the length of the diagonal in the square

To find the length of the diagonal of a square, use the Pythagorean Theorem (a^2 + b^2 = c^2) ... You know that "a" and "b" are the same in this case, so it becomes square_root of 2 x (side_length2) ... which you can simplify as "multiply by the square root of 2"