Doesn't seem likely, does it? A diagonal 50 times the length of the sides?
Diagonal = sqrt(252 + 252), ie sqrt 1250(!) which is 35.36 to the nearest hundredth.
Not always, the diagonal can be figured out using the Pythagorean Theorem (a²+b²=c²). Where the diagonal is the hypotenuse (c). By rearranging the Pythagorean Theorem, you can see that the diagonal of a square is always 1.4 times the side of the square.
To find the length of the diagonal of a square, we can use the Pythagorean theorem. In a square, the diagonal divides the square into two right-angled triangles. The Pythagorean theorem states that the square of the length of the diagonal is equal to the sum of the squares of the two sides. Therefore, for a 10 by 10 ft square, the length of the diagonal would be the square root of (10^2 + 10^2) which is √(100 + 100) = √200 = 10√2 feet.
d=x√2 where d is a diagonal and x is a side d=80√2 (or 113.137)
By the Pythagorean Theorem, it's simply L*Sqrt(2), where L is the length of the side, and Sqrt denotes the square root.
diagonal="c" side=9="9"="9" sincec^2=b^2+a^2, diagonal=square root of(2(9^2))=
Not always, the diagonal can be figured out using the Pythagorean Theorem (a²+b²=c²). Where the diagonal is the hypotenuse (c). By rearranging the Pythagorean Theorem, you can see that the diagonal of a square is always 1.4 times the side of the square.
The diameter of the circle is congruent to the length of the diagonal of the inside square. If you know the length of one side of the square, you can use pythagorean's theorem to solve for its diagonal (hypotenuse) and thusly the square's diameter.
Squares do not have diameters; circles have them. If you are referring to the diagonal of a square, then you would use Pythagorean's Theorem to determine the length of the diagonal. 'Square' the length of one side and multiply by 2, then take the square root of that number to get the length of the diagonal. that is = under root( 2 s) where s= side
Each side of the square is 20 inches and by using Pythagoras' theorem its diagonal is 20 times the square root of 2 which is about 28.284 inches rounded to 3 decimal places.
To find the length of the diagonal of a square, we can use the Pythagorean theorem. In a square, the diagonal divides the square into two right-angled triangles. The Pythagorean theorem states that the square of the length of the diagonal is equal to the sum of the squares of the two sides. Therefore, for a 10 by 10 ft square, the length of the diagonal would be the square root of (10^2 + 10^2) which is √(100 + 100) = √200 = 10√2 feet.
d=x√2 where d is a diagonal and x is a side d=80√2 (or 113.137)
By the Pythagorean Theorem, it's simply L*Sqrt(2), where L is the length of the side, and Sqrt denotes the square root.
diagonal="c" side=9="9"="9" sincec^2=b^2+a^2, diagonal=square root of(2(9^2))=
Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.
To find the side length of a square with a diagonal of 5, we can use the Pythagorean theorem. The diagonal of a square divides it into two 45-45-90 right triangles. Let x be the side length of the square. Using the Pythagorean theorem, we have x^2 + x^2 = 5^2. Simplifying, we get 2x^2 = 25. Solving for x, we find x = √(25/2) = √12.5 = 3.54 (rounded to two decimal places). Therefore, the side length of the square is approximately 3.54 units.
Use Pythagoras' theorem to find the length of the diagonal in the square
length2+width2 = diagonal2 and the square root of this is the size of the diagonal