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To solve this problem, you first need to define some variables and then set up an equation. Let w = width of the rectangle and l = length of the rectangle. Since the length is 9 m longer than the width, we can write the following: w = width w + 9 = length Since the area of a rectangle is found by multiplying length x width, we can write the following equation: w(w + 9) = 36 Next, we must solve this equation. By the distributive property, we have w^2 + 9w = 36. Subtracting 36 from both sides, we get w^2 + 9w - 36 = 0 We can factor this trinomial into (w + 12)(w - 3) = 0 By the zero product property, we have w + 12 = 0 or w - 3 = 0 Solving these two equations, we have that w = -12 or w = 3. Since the width of a rectangle cannot be negative, we ignore the w = -12 solution and we find that w = 3. Since our width is 3 m, our length must be 12 m. We can check our answer by verifying that 12 m x 3m = 36 m^2.
Surface area = 2*(L*W + W*H + H*L) = 324 m2
Perimeter = 2(L + W) = 2*(5.5 + 12) m = 2*17.5m = 35 m.
as you are trying to work out the area. W x L = area. So. 5m x 6m = 30m2
W=L*A width equals length times area