L + W = 87. L = 2W + 9 so (2W + 9) + W = 87 ie 3W = 78 so Width is 26 m and Length is 61 m.
To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the length is 5.5 meters and the width is 3.25 meters. The formula for the perimeter of a rectangle is P = 2(length + width). Therefore, the perimeter of this rectangular lot would be P = 2(5.5 + 3.25) = 2(8.75) = 17.5 meters.
The perimeter of a square is 400 meters. write an equation for the perimeter and solve for the length of one side
the length of a rectangular garden is 12 meters and the width is 7 meters. What is the area
Perimeter: 12+25+12+25 = 74 meters
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
The length is 10 meters and the width is 5 meters
length = 22 meters and width = 6 meters
The length of the floor is 5.5 meters because 2*(5.5+5) = 21 meters which is the perimeter
The dimensions are 7 by 12 meters Check: perimeter = 2*(7+12) = 38 meters and area = 7*12 = 84 square meters
You shoulda done your homework.
Width: 16 meters Length: 21 meters Check: 16+21+16+21 = 74 meters which is its perimeter
5 km or 5000 meters
The length of the rectangle is 27 meters and the width is 19 meters.
1 x 5 2 x 4 3 x 3
To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the length is 5.5 meters and the width is 3.25 meters. The formula for the perimeter of a rectangle is P = 2(length + width). Therefore, the perimeter of this rectangular lot would be P = 2(5.5 + 3.25) = 2(8.75) = 17.5 meters.
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
A ziggurat could be oval, rectangular, square, or any other shape. If happened to have a square base, its perimeter would be four times its length (4 x 22 meters = 88 it meters).