L + W = 87. L = 2W + 9 so (2W + 9) + W = 87 ie 3W = 78 so Width is 26 m and Length is 61 m.
The perimeter of a square is 400 meters. write an equation for the perimeter and solve for the length of one side
the length of a rectangular garden is 12 meters and the width is 7 meters. What is the area
Perimeter: 12+25+12+25 = 74 meters
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
Designate the width by w. Then, from the problem statement, the length = 6 + 2w. The perimeter is twice the width plus twice the length, or: 2w + 2(2w + 6) = 36; or 2w + 4w + 12 = 36; or 6w = 24 or w = 4 meters; the length is 14 meters.
length = 22 meters and width = 6 meters
The length is 10 meters and the width is 5 meters
The length of the floor is 5.5 meters because 2*(5.5+5) = 21 meters which is the perimeter
The dimensions are 7 by 12 meters Check: perimeter = 2*(7+12) = 38 meters and area = 7*12 = 84 square meters
You shoulda done your homework.
Width: 16 meters Length: 21 meters Check: 16+21+16+21 = 74 meters which is its perimeter
5 km or 5000 meters
1 x 5 2 x 4 3 x 3
The length of the rectangle is 27 meters and the width is 19 meters.
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
A ziggurat could be oval, rectangular, square, or any other shape. If happened to have a square base, its perimeter would be four times its length (4 x 22 meters = 88 it meters).
The perimeter of a square is 400 meters. write an equation for the perimeter and solve for the length of one side