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What is the perimeter of a rectangular lot with a length of 5.5 m and a width of 3.25?
To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the length is 5.5 meters and the width is 3.25 meters. The formula for the perimeter of a rectangle is P = 2(length + width). Therefore, the perimeter of this rectangular lot would be P = 2(5.5 + 3.25) = 2(8.75) = 17.5 meters.
The perimeter of a square depends on the length of its sides A square with a side length of 4 meters has a perimeter of 16 meters A square with a side length of 6 meters has a perimeter of 24 meters?
The perimeter of a square is 400 meters. write an equation for the perimeter and solve for the length of one side
What length of a rectangular with12 meters and the width 7 meters?
the length of a rectangular garden is 12 meters and the width is 7 meters. What is the area
A rectangular factory is 12 meters wide and 25 meters long what is its perimeter?
Perimeter: 12+25+12+25 = 74 meters
What is the perimeter of a rectangle that is 1.6 meters long and 0.8 meters wide?
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
The perimeter of a rectangular field is 30 meters. The width is one-half the length.If the length and width are whole numbers what are the dimensions of the field?
The length is 10 meters and the width is 5 meters
The length of a rectangular garden is 4 meters more than 3 times its width the perimeter of the garden is 56m What are the dimensions of the garden?
length = 22 meters and width = 6 meters
A rectangular tile floor has a width of 5 meters and a perimeter of 21 meters. Which of these is the length of the floor?
The length of the floor is 5.5 meters because 2*(5.5+5) = 21 meters which is the perimeter
What is the answer of the area of a rectangular field is 84 sq meter and its perimeter is 38 meters Find the dimensions of the field?
The dimensions are 7 by 12 meters Check: perimeter = 2*(7+12) = 38 meters and area = 7*12 = 84 square meters
The perimeter of a rectangular yard is 66 meters and its area is 270 square meters Find the dimensions of the yard?
You shoulda done your homework.
What are the length and width of a of a rectangular hall whose perimeter is 74 meters and whose length is 5 meters more than its width?
Width: 16 meters Length: 21 meters Check: 16+21+16+21 = 74 meters which is its perimeter
What is the perimeter of a rectangular park with a width of 500 meters and a length of 2 kilometers?
5 km or 5000 meters
What are the dimensions of the largest rectangular pen that can be enclosed with 64 meters of fence?
To find the dimensions of the largest rectangular pen that can be enclosed with 64 meters of fence, we can use the formula for the perimeter of a rectangle, which is (P = 2(l + w)), where (l) is length and (w) is width. Setting the perimeter equal to 64 meters gives us (l + w = 32). To maximize the area (A = l \times w), we can express (w) as (w = 32 - l) and find the maximum area occurs when (l = w = 16). Therefore, the dimensions of the largest rectangular pen are 16 meters by 16 meters, making it a square.
What is the length of a rectangular lot with a perimeter of 72 m if the length is 8 m more than the width?
The length of the rectangle is 27 meters and the width is 19 meters.
A rectangular has a perimeter of 12 meter if each side is a whole number of meters what are the possible dimensions for the length and width?
1 x 5 2 x 4 3 x 3
What is the perimeter of a rectangular lot with a length of 5.5 m and a width of 3.25?
To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the length is 5.5 meters and the width is 3.25 meters. The formula for the perimeter of a rectangle is P = 2(length + width). Therefore, the perimeter of this rectangular lot would be P = 2(5.5 + 3.25) = 2(8.75) = 17.5 meters.
What are the dimensions of a parking lot with the area of 918 square meters and the perimeter of 122meters?
To find the dimensions of a parking lot with an area of 918 square meters and a perimeter of 122 meters, we can set the length as ( l ) and the width as ( w ). The equations are ( lw = 918 ) and ( 2(l + w) = 122 ). Solving these equations simultaneously, we find that the dimensions are approximately 39 meters in length and 23.5 meters in width.
