24 meters
Perimeter (distance around the outside) = two lengths and two widths
P = 2L + 2W
2 (7) + 2(5) = 24
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16 metres.
The perimeter of a rectangle is calculated by adding the lengths of all its sides. In this case, the rectangle has a length of 7 meters and a width of 3 meters. To find the perimeter, you would add the lengths of all sides: 7m + 7m + 3m + 3m = 20 meters. Therefore, the perimeter of a rectangle with dimensions 7m x 3m is 20 meters.
well if you add it it is easy. A:11m.The above is a load of bovine droppings. P = 2(L + W) so the CORRECT answer is 22 m.The perimeter of a rectangle is 2 x (length + width).2 x (7m + 4m) = 2 x 11m = 22m
The perimeter of the hexagon will be 30m (5m x 6 edges = 6 x 5 = 30m)
Rectangles are really simple. The perimeter is twice the length plus twice the width (in this case 4m x 2 = 8m, 5m x 2 = 10m, and 8m + 10m = 18m). The area is simply the length times the width (in this case, 4m x 5m = 20m2).
16 metres.
11x5 m is 32m
The area of rectangle is : 56.0
32 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (9) + 2 (7) = 18 + 14 = 32 also: P = 2 (L + W) 2(9 + 7) = 32
35 m2
well if you add it it is easy. A:11m.The above is a load of bovine droppings. P = 2(L + W) so the CORRECT answer is 22 m.The perimeter of a rectangle is 2 x (length + width).2 x (7m + 4m) = 2 x 11m = 22m
90m. hey um can u explain how to work tht out plez? thanks -Mikeman97
9m x 5m = 45 m2
The perimeter of the hexagon will be 30m (5m x 6 edges = 6 x 5 = 30m)
28 meters It would be a square because A = L x W so 49 = 7 x W and the width is 7. Its perimeter is 4*7 = 28 meters.
Rectangles are really simple. The perimeter is twice the length plus twice the width (in this case 4m x 2 = 8m, 5m x 2 = 10m, and 8m + 10m = 18m). The area is simply the length times the width (in this case, 4m x 5m = 20m2).
That depends on the dimensions !... A 1 x 18 rectangle has a perimeter of 38 ! A 2 x 9 rectangle has a perimeter of 22 ! A 3 x 6 rectangle has a perimeter of 18 !