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What is the point slope form of the equation of the line through -1 -6 and -2 10?
Wiki User
∙ 14y ago
Let (x1, y1) = (-1, -6) and (x2, y2) = (-2, 10). Then the slope,
m = (y2 - y1)/(x2 - x1) = (10 - -6)/(-2 - -1) = 16/-1 = -1/16.
So that the point-slope form of the equation of the given line is:
(y - y1) = m(x - x1)
(y - -6) = (-1/16)(x - -1)
(y + 6) = (-1/16)(x + 1)
Wiki User
∙ 14y ago
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