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Another point is needed to work out the slope and its straight line equation. Slope is worked out as: (y2-y1)/(x2-x1)

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With slope m and going through a point (x0, y0), a line has equation:

y - y0 = m(x - x0)

Thus the point-slope equation of a line with slope m through the point (-1, 2) is given by:

y - 2 = m(x - -1)

→ y - 2 = m(x + 1)

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Q: What is the point-slope form of a line with slope that contains the point (-1 2)?
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