One possible conjecture: The product is always an odd number. Another possible conjecture: The product is always greater than either of them. Another possible conjecture: Both odd numbers are always factors of the product. Another possible conjecture: The product is never a multiple of ' 2 '. Another possible conjecture: The product is always a real, rational number. Another possible conjecture: The product is always an integer.
17,19,21
Let's take a look at this. For any integer n, 2n always be even, then the next consecutive number 2n + 1 must be odd. Let add them first, 2n + 2n + 1 = 4n + 1 = 2(2n) + 1 So their sum is odd, since every even number multiplied by 2 is also even. Let's multiplied them, 2n(2n + 1) = (2n)^2 + 2n Their product is even, since every even number raised in the second power is also even, and the sum of two even numbers is even too. So the answer is that when the sum of two numbers can be odd, their product is an even number. (note that the sum of two odd numbers is even)
the product of two integers is odd if and only if the two factors are odd
If two numbers are reciprocals, then their product is 1. If the product of two numbers is 1, then they are reciprocals.
The product of two odd numbers is always odd.
No such numbers exist; the product of two odd numbers is always odd.
The product of two odd numbers is always odd.
Any two odd numbers will have an odd product and an even sum.
The product of odd number is always odd.
I guess you mean "product" - the product of two odd numbers is odd. (For example, 3x3=9, 5x3=15, etc.
The product of two odd numbers is never even.
The product of any two odd numbers is an odd number. The product means that it is the outcome of a multiplication. 3 * 5 = 15, 5 * 7 = 35.
no
an odd number
No two odd numbers can sum to 7.
More than possible. Unless one of your prime numbers is 2, the product of any other two will be odd.