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The product of which 3 consecutive odd numbers 6783?
17,19,21
What is a conjecture for multiplying two odd numbers?
One possible conjecture: The product is always an odd number. Another possible conjecture: The product is always greater than either of them. Another possible conjecture: Both odd numbers are always factors of the product. Another possible conjecture: The product is never a multiple of ' 2 '. Another possible conjecture: The product is always a real, rational number. Another possible conjecture: The product is always an integer.
Is the sum of 2 numbers can be odd then there product is odd as well?
Let's take a look at this. For any integer n, 2n always be even, then the next consecutive number 2n + 1 must be odd. Let add them first, 2n + 2n + 1 = 4n + 1 = 2(2n) + 1 So their sum is odd, since every even number multiplied by 2 is also even. Let's multiplied them, 2n(2n + 1) = (2n)^2 + 2n Their product is even, since every even number raised in the second power is also even, and the sum of two even numbers is even too. So the answer is that when the sum of two numbers can be odd, their product is an even number. (note that the sum of two odd numbers is even)
What of the following is a true biconditional statement?
the product of two integers is odd if and only if the two factors are odd
If the product of two numbers is even then the two numbers must be even?
At least one of the two numbers has to be even, but both can be even.
