no
Note!!!! ignore the S at the end these are the questions 1. side AC= 31 cm, side BC= 20 cm and angle B= 58 degrees 2. side AC= 21 cm, side BC= 28 cm and side AB= 32 cm 3. side AC= 8 cm and side AB= 10 cm please help last 3 questions of my homework. My teacher collects it =(
The minimum value of the parabola is at the point (-1/3, -4/3)
There are 43,560 sq. ft. in 1 Ac.
1/3 bh x h divided by 2 It depends on the dimensios of the cuboid (rectangular prism). If it has edge lengths a,b and c then it is made of three pairs of rectangles of area ab, ac and bc. So suface area = 2(ab + bc + ca)
2
no
since BC=1/2 AC you take half of 54 then solve the equation. 3x^2=54/2 3x^2=27 x^2=9 x=3
Take a right angled triangle ABC with the right angle at B, so that AC is the hypotenuse. Let AC be 1 unit long. Using the angle CAB, the length of AC and the trigonometric ratios: sin = opposite/hypotenuse ⇒ sin CAB = AB/AC = AB/1 = AB cos = adjacent/hypotenuse ⇒ cos CAB = BC/AC = BC/1 = BC Using Pythagoras: AB2 + BC2 = AC2 ⇒ (sin CAB)2 + (cos CAB)2 = 12 ⇒ sin2θ + cos2θ = 1
The probability of ac and bc is 1/5.
AC=5 AB=8 A=1 B=8 C=5 BC=40
By use of the sine rule: sin A / BC = sin B / AC = sin C / AB Angles B and C are known, as is length AC, so: sin B / AC = sin C / AB AB = AC x sin C / sin B AB = 17cm x sin 24 / sin 95 ~= 6.94cm The ratios for the sine rule can also be given the other way up: BC / sin A = AC / sin B = AB / sin C (I learnt the rule the first way.) Further, if r is the radius of the triangle's circumcircle, then: sin A / BC = 1/2r or BC / sin A = 2r
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
A = (1/2)(ac)(bd) = (1/2)(8)(9) = 36
It does bc 69 is awesome
The only way this could be true is under one of the following conditions:a, b and c are all equal to zerob is equal to 1 and a is equal to cb is equal to -1 and a is equal to -cConsider:ab = cbc = aFirst, plug the second equation into the first one to find the value of b:(bc)(b) = cb2c = cb2 = 1b = ±1Now take those values and plug it into either equation:(1)(c) = ac = aor:(-1)(c) = ac = -aTo prove that the absolute values of c and a must be identical:Given:ab = cbc = aThen:ab/c = 1bc/a = 1Therefore:ab/c = bc/aa2b = bc2a2 = c2|a| = |c|
Yes, for example (a + bi)(c + di) = ac + adi + bic + bidi, and commutative property works as well --> ac + adi + bci + bdi² --> ac + (ad + bc)i + bd(-1) = (ac - bd) + (ad + bc)i