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The square has perimeter Ps equal to 4L (where L is the side length of the square) and L equal to √(As) (where A is the area and subscript 's' indicates we are talking about the area of the square). From this we can rearrange to 4√(As). The circle has perimeter Pc equal to π(2R) (where R is the radius of the circle) and R equal to √(Ac/ π) (where subscript 'c' indicates we are talking now talking about the area of the circle) or, the square root of the circle's area divided by pi. From this we can rearrange to 2π√(Ac/ π). Since we know the perimeters are equal, Ps = Pc; we can then put the right sides together to get 4√(As) = 2π√(Ac/ π). Through rearranging of this equation, we can reduce to 4As = πAc. As a ratio, this comes down to As:Ac à π:4.

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