polyhedrons need flat face and edges, corners which cylinder cones don't have.
Two polyhedrons have 18 edges: truncated tetrahedron and hexagonal prism.
I can just think of the pentagonal pyramid.
Yes. to add to that a vertex must be connected to at least 3 edges to be 3d, an edge is always connected to 2 vertexes, so the closest the two can ever be is vetexes x 3 = edges x 2, but when working with any platonic solid you can follow this: vertexes x (faces / vertexes) x [edges on one side] = edges x 2 or vertexes x [faces meeting at one vertex] = edges x 2 when working with any other polyhedron [vertexes with x amount of faces] x (x) + [vertexes with y amount of faces] x (y) ...{and so on} = edges x 2
For a simply connected polyhedra, the Euler characteristic requires that E + 2 = F + V
A cuboid douses have 8 verticess and 12 edges.
polyhedrons need flat face and edges, corners which cylinder cones don't have.
4 edges A rectangle has four edges. A rectangle has 4 sides but no edges which are normally applicable to polyhedrons.
polyhedrons need flat face and edges, corners which cylinder cones don't have.
Two polyhedrons have 18 edges: truncated tetrahedron and hexagonal prism.
I can just think of the pentagonal pyramid.
Cylinders and cones are not considered polyhedrons because they do not have flat faces, which is a defining characteristic of polyhedrons. Polyhedrons are three-dimensional shapes made up of flat surfaces, while cylinders and cones have curved surfaces. Additionally, polyhedrons have straight edges where faces meet, whereas cylinders and cones have curved edges. Therefore, cylinders and cones are classified as curved surfaces rather than polyhedrons.
No. There must be at least three but theyre can be more.
No. For example, a cube is a polyhedron and 3 edges meet at each vertex.
Add the number of faces of the shape to the number of vertices, and then subtract 2 to give you the number of edges. This works for most polyhedrons. I hope I have helped :) ALSO, take the number of vertices, divide that by two, then add that answer to the number of vertices... that will give you the number of edges unless it is a pyramid. Here is one that is GURANTEED TO WORK BECAUSE I HAVE TRIED IT. Here is is: Edge= 2 times(Vertice-1)
you take face, than add the vertice, and subtract 2 from it this works for almost al polyhedrons but it doesn't work for a cylinder
pentagonal antiprism, pentagonal deltohedron(not deltahedron), decagonal pyramid, and many more.