The sum of the exterior angles of a polygon is 360o.
For a regular polygon, each exterior angle is the same, thus
number_of_sides x exterior_angle = 360o
⇒ exterior_angle = 360o ÷ number_of_sides.
A hendecagon has 11 sides, thus:
exterior_angle = 360o ÷ 11 = 328/11o ~= 32.7o
⇒
An exterior angle of any polygon can have any value between 0 and 360 degrees apart from 180 degrees.
135 degrees and its exterior angle is 45 degrees
Exterior angle+interior angle=180 degrees and 180-exterior angle=interior angle
It is: 180-interior angle = exterior angle
An exterior angle of a decagon can have any value in the range (0, 360) degrees - excluding 180 degrees. The only constraint is that the sum of all exterior angles must be 360 degrees.
Hendecagon
regular hendecagon has internal angles of 147.27 degrees. The area of a regular hendecagon with side length a is given byA regular hendecagon is not constructible with compass and straightedge; this animation shows an approximation:
No because each interior angle increases in size whereas each exterior angle decreases in size.
Each exterior angle is 360/6 = 60 degrees
Interior angles are 108o. 360 - 108 = 252o for each exterior angle * * * * * Each exterior angle is 360/5 = 72 degrees, NOT 252. The 108 for the interior angle is correct, but to get from interior to exterior you subtract from 180, not 360!
Exterior angles are supplementary with interior angles, so 180-30=150
An exterior angle of any polygon can have any value between 0 and 360 degrees apart from 180 degrees.
exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°
360/8 = 45 degrees
The sum total of all exterior angles of any polygon is 360 degrees. So if you're given thevalue of one exterior angle AND THE POLYGON IS REGULAR(all exterior angles are thesame size), all you have to do is divide the size of one angle into 360, and the quotientis the number of sides.
It is: 180-24 = 156 degrees
135 degrees and its exterior angle is 45 degrees