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The sum of the exterior angles of a polygon is 360o.

For a regular polygon, each exterior angle is the same, thus

number_of_sides x exterior_angle = 360o

⇒ exterior_angle = 360o ÷ number_of_sides.

A hendecagon has 11 sides, thus:

exterior_angle = 360o ÷ 11 = 328/11o ~= 32.7o

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Q: What is the size of an exterior angle in a hendecagon?
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What shape has an exterior angle of 32.7 degrees?

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