y - x = 0 which is the same as
y = x + 0 which is of the form y = mx + c where m is the slope and c is the intercept. Hence for y = x + 0, the slope is 1 ans the intercept is 0. The equation represents a line making 45 degrees to the a-axis and it passes through the origin.
No. In a linear equation, y = mx + b, the slope is m, and the x intercept is where mx + b = 0.
y + 4 = 0 y = 0x - 4 The graph is a straight horizontal line. Its slope is zero. The y-intercept is -4. There is no x-intercept.
y = mx + b y = 0.666666666666666666667(x) + 6 m = slope b = y intercept
x-3y=3 is the same as -3y=-x+3 and now divide by -3 and you have y=(1/3)x-1 which is the slope intercept form.
x - 9y = 18At the x-intercept, y=0 :x = 18At the y-intercept, x=0 :-9y = 18-y = 2y = -2
y = x + 0
m = slope b = y intercept ( value when x =0)
5
y = x
Slope is zero y-intercept is -7 there is no x-intercept for this equation
Slope is -1 y-intercept is 1 x-intercept is 1
There is no y intercept, it is a straight verticle line a x = -6. And technically it has "infinite" slope (1/0), but it is more common to say "No slope".
No it is not an undefined slope; the slope of y = -x is -1.The standard form of a linear equation is y = mx + b, where m is the slope, and b is the y-intercept. In y = -x, the y-intercept is 0, and the slope is -1.
slope = -1y-intercept = 5
The given equation is : x + 5 + y = 0 Write in standard form of equation of straight line : y = mx + c . Where m is slope and c is y-intercept. We get: y = -x - 5 Which gives slope = -1 y-intercept = -5 To get x-intercept put y = 0 in the equation. We get x-intercept = -5
y=mx+b in slope intercept form m=slope b=y-intercept
Yes, it is possible only when the x-intercept is infinite. so slope=y/x = 0.