maybe
If Y = 0 then there is no value of X such that XY = 1.
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
It is sqrt(0), which equals 0.
To find the xy-trace, set z = 0 in the equation -5x - 2y - 3z = 10. Simplifying, we get -5x - 2y = 10. This is the equation of the xy-trace for the given plane.
maybe
If Y = 0 then there is no value of X such that XY = 1.
"xy" refers to the product of "x" and "y". Just substitute the variables for numbers, and do the multiplication.
xy - xy = 0
There are no intercepts because the curve, xy = 4 is asymptotic. When x = 0 (where the y intercept would be) y is infinite, and conversely, when y = 0 x is infinite.
Using 3.14 as Pi the area of circle is: 0
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
3Y - 12X = 0add 12X to both sides3Y = 12Xdivide both sides integers by 3(3/3)Y = (12/3)XY = 4X---------------the function
It is sqrt(0), which equals 0.
To find the xy-trace, set z = 0 in the equation -5x - 2y - 3z = 10. Simplifying, we get -5x - 2y = 10. This is the equation of the xy-trace for the given plane.
a(-14-a) = 0 so a = 0 or a = -14
Using: x - 2y = 8 y = (x - 8)/2 Substituting in: xy = 24 => x(x - 8)/2 = 24 => x2 - 8x = 48 => x2 - 8x - 48 = 0 => (x - 12)(x + 4) = 0 => x = 12 or -4 => y = 2 or -6 respectively (since xy = 24) ie the points (12, 2) and (-4, -6)