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How do find x and y intercepts without a graph?
If for example: y = 2x+4 Then: y-2x = 4 And when the value of x is 0 then the y intercept is 4 And when the value of y is 0 then the x intercept is -2
If mbad equals 5x plus 8 and mbcd equals 7x - 4 then mabc equals?
548
What is the straight line equation passing through points 4 and 0 when it is perpendicular to x plus 7y plus 4 equals 0?
x+7y+4 = 0 => y = -1/7x-4/7 The slope of the second equation is the reciprocal of the first equation with the minus sign changing to a plus sign. y = mx+c where m is the slope and c is the intercept on the y axis So: 7*4+c = 0 28+c = 0 c = -28 Therefore the perpendicular equation is: y = 7x-28 which can be expressed in the form of 7x-y-28 = 0
What are the intercepts for the line -4x y 8?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. If your question is not answered, please resubmit it, spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (x^2) or x-squared.Restate the question: What are the intercepts of the line -4x + y = 8?To find the y-intercept, let x=0: -4(0)+y=8 y=8To find the x-intercept, let y=0: -4x+(0)=8 -4x=8 -4x/(-4)=8/(-4) x=-2With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!Also note that most texts define an intercept as a number ("the y-intercept is 8"), but it is rare to consider "The y-intercept is (0,8)." to be correct.
What is the centre and radius of the circle 4x2 plus 4y2 plus 16x -32y plus 71 equals 0?
Equation: 4x^2 +4y^2 +16x -32y +71 = 0 Divide all terms by 4: x^2 +y^2 +4x -8y +71/4 = 0 Complete the squares: (x+2)^2 +(y-4)^2 -4 -16 +71/4 = 0 So: (x+2)^2 +(y-4)^2 = 9/4 which is the radius squared Therefore centre of circle is at (-2, 4) and its radius is 3/2 or 1.5
