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What is the point-slope equation of a line with slope -3 that contains the point (-8 -4)?
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
What is the equation of the tangent line that meets the circle x2 -4x plus y2 -6y equals 4 at the point 6 4?
Circle equation: x^2 -4x +y^2 -6y = 4 Completing the squares: (x-2)^2 +(y-3)^2 = 17 Point of contact: (6, 4) Center of circle: (2, 3) Slope of radius: 1/4 Slope of tangent line: -4 Tangent equation: y-4 = -4(x-6) => y = -4x+28 Tangent line equation in its general form: 4x+y-28 = 0
What is the straight line equation passing through points 4 and 0 when it is perpendicular to x plus 7y plus 4 equals 0?
x+7y+4 = 0 => y = -1/7x-4/7 The slope of the second equation is the reciprocal of the first equation with the minus sign changing to a plus sign. y = mx+c where m is the slope and c is the intercept on the y axis So: 7*4+c = 0 28+c = 0 c = -28 Therefore the perpendicular equation is: y = 7x-28 which can be expressed in the form of 7x-y-28 = 0
If AB equals 21 centimeters and BC equals 28 centimeters what does AC equal?
12
What is the radius of 28 cm?
It is the name given to the straight line from the centre of a circle to its circumference when that distance is 28 cm.
