If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
Circle equation: x^2 -4x +y^2 -6y = 4 Completing the squares: (x-2)^2 +(y-3)^2 = 17 Point of contact: (6, 4) Center of circle: (2, 3) Slope of radius: 1/4 Slope of tangent line: -4 Tangent equation: y-4 = -4(x-6) => y = -4x+28 Tangent line equation in its general form: 4x+y-28 = 0
x+7y+4 = 0 => y = -1/7x-4/7 The slope of the second equation is the reciprocal of the first equation with the minus sign changing to a plus sign. y = mx+c where m is the slope and c is the intercept on the y axis So: 7*4+c = 0 28+c = 0 c = -28 Therefore the perpendicular equation is: y = 7x-28 which can be expressed in the form of 7x-y-28 = 0
12
It is the name given to the straight line from the centre of a circle to its circumference when that distance is 28 cm.
Slope = -1
28
14y - 2x = 28 ie 7y - x = 14 ie 7y = x + 14 or y = (1/7)x + 14 The slope is the coefficient of x, or 1/7
-4x=7y-28 -4x+28=7y -4x/7+4=y A line with a y-int of 4 and a slope of -4/7
(28/17,7/17) The point on the line closest to the origin is the point on a line through the origin that is perpendicular to the given line. Because the slope of the perpendicular is the negative reciprocal of the given line, it has a slope of -1/4 and is given by the equation: y=(-1/4)x The x-coordinate of the point of intersection is found by solving the following: (-1/4)x=4x+7 -x=16x+28 -17x=28 x=-28/17 y=(-1/4)(-28/17)=7/17
If: 4x-7y-28 = 0 then y = 4/7x-4 whereas 4/7 is the slope and -4 is the y intercept
y=-(8/7)x+4 Therefore, the slope= -(8/7)
In the equation: y = mx + c m is the gradient (or slope) and c is the point at which the line crosses the y-axis. Therefore, we are looking to determine m. Your equation is: 4x + 7y = 28 Let's rearrange this as follows: 7y = -4x + 28 Now divide by 7 throughout: y = (-4/7)x + 4 Therefore, m = -4/7, or -0.5714
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
How to find slope if you are given the equation of a line in slope-intercept form:Slope intercept form is y = mx + b. m is the slope.For example, the slope of the line y = 3x + 7 is 3. (3 is m in the equation y = mx + b.) Another example, the slope of the line y = (-5/4)x - 4 is -5/4.If the line is in the form y = a number, then the slope is 0. For example, the slope of the line y = 3 is 0.If the line is int the form x = a number, then the slope is undefined. For example, the slope of the line x = 5 is undefined.How to find slope if you are given the equation of a line in point-slope form:Point slope form is y - y1 = m(x - x1). m is the slope.For example, the slope of the line y-6 = 2(x-7) is 2. Another example, the slope of the line y-5 = (3/2)(x+4) is 3/2.How to find the slope if you are given the equation of a line in standard form:Standard form is ax + by = c.One way to find the slope if a line in standard form is to convert it to slope-intercept form (y=mx+b).Here is an example using the line 3x + 8y = 283x + 8y = 28First move the x to the other side by subtracting 3x from each side:8y = 28 - 3xNext, divide each side by 8 (all three terms must be divided by 8):y = 28/8 - (3/8)xAfter simplifying the fractions, the formula is y = 7/2 - (3/8)xSlope-intercept form is y = mx + b, so the terms on the left side of the equation need to be rearranged for it to truly be in slope-intercept form:y = -(3/8)x + 7/2Be sure to keep the negative signs in front of their terms! (if you have any negative sings, there will be times when you won't.)The equation of the line 3x + 8y = 28 in slope-intercept form isy = -(3/8)x + 7/2. The slope of this line is -3/8 (see How to find slope if you are given the equation of a line in slope-intercept form, above).Another, faster way is to use the formula -a/b. The slope of the line 3x + 8y = 28 is -3/8. (Remember, this only works for standard form (ax + by = c).)