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What is the point-slope equation of a line with slope -3 that contains the point (-8 -4)?
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
What is the equation of the tangent line that meets the circle x2 -4x plus y2 -6y equals 4 at the point 6 4?
Circle equation: x^2 -4x +y^2 -6y = 4 Completing the squares: (x-2)^2 +(y-3)^2 = 17 Point of contact: (6, 4) Center of circle: (2, 3) Slope of radius: 1/4 Slope of tangent line: -4 Tangent equation: y-4 = -4(x-6) => y = -4x+28 Tangent line equation in its general form: 4x+y-28 = 0
What is the straight line equation passing through points 4 and 0 when it is perpendicular to x plus 7y plus 4 equals 0?
x+7y+4 = 0 => y = -1/7x-4/7 The slope of the second equation is the reciprocal of the first equation with the minus sign changing to a plus sign. y = mx+c where m is the slope and c is the intercept on the y axis So: 7*4+c = 0 28+c = 0 c = -28 Therefore the perpendicular equation is: y = 7x-28 which can be expressed in the form of 7x-y-28 = 0
If AB equals 21 centimeters and BC equals 28 centimeters what does AC equal?
12
What is the radius of 28 cm?
It is the name given to the straight line from the centre of a circle to its circumference when that distance is 28 cm.
What is the slope of -y equals x-28?
Slope = -1
What is the slope of the line y equals 7x-21?
28
What is the slope of the line 14y-2x equals 28?
14y - 2x = 28 ie 7y - x = 14 ie 7y = x + 14 or y = (1/7)x + 14 The slope is the coefficient of x, or 1/7
What is the graph of -4x plus 7y equals -28?
-4x=7y-28 -4x+28=7y -4x/7+4=y A line with a y-int of 4 and a slope of -4/7
Find the point on the line y equals 4x plus 7 that is closest to the origin?
(28/17,7/17) The point on the line closest to the origin is the point on a line through the origin that is perpendicular to the given line. Because the slope of the perpendicular is the negative reciprocal of the given line, it has a slope of -1/4 and is given by the equation: y=(-1/4)x The x-coordinate of the point of intersection is found by solving the following: (-1/4)x=4x+7 -x=16x+28 -17x=28 x=-28/17 y=(-1/4)(-28/17)=7/17
What is the slope of 4x-7y-28 equals 0?
If: 4x-7y-28 = 0 then y = 4/7x-4 whereas 4/7 is the slope and -4 is the y intercept
Find the slope of the line 4x plus 7y equals 28?
In the equation: y = mx + c m is the gradient (or slope) and c is the point at which the line crosses the y-axis. Therefore, we are looking to determine m. Your equation is: 4x + 7y = 28 Let's rearrange this as follows: 7y = -4x + 28 Now divide by 7 throughout: y = (-4/7)x + 4 Therefore, m = -4/7, or -0.5714
Find the slope of the equation 8x plus 7y equals 28?
y=-(8/7)x+4 Therefore, the slope= -(8/7)
What is the point-slope equation of a line with slope -4 that contains the point (-27)?
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
What is the point-slope equation of a line with slope -4 that contains the point (-2 7)?
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
What is the point-slope equation of a line with slope -3 that contains the point (-8 -4)?
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
What is y equals 12x plus 28?
The equation ( y = 12x + 28 ) represents a linear function where ( y ) is expressed in terms of ( x ). In this equation, 12 is the slope, indicating that for every unit increase in ( x ), ( y ) increases by 12 units. The constant term 28 is the y-intercept, meaning that the line crosses the y-axis at the point (0, 28). This equation describes a straight line when graphed on a coordinate plane.
