4x-2y = 10 -2y = -4x+10 y = 2x-5 which is now in slope-intercept form
okay, so to find this the format of the equation is y=mx+b, where m is the slope, and b is the y-int. 4x-3y=6 simplified to that format is: y=1.3333...x+2, so the slope is 1 and 1/3, and the y-int. is 2.
Slope intercept form looks like y=mx+b, so we want to get y on on side by itself. -4x+2y=2 Add 4x to both sides: 2y=2+4x Divide both sides by 2: y=1+2x or y=2x+1
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept.By using the slope, m = 4 and the point (x1, y1) = (2, 1), write the point-slope equation of a line:(y - y1) = m(x - x1)(y - 1) = 4(x -2)y - 1 = 4x - 8 add 1 to both sidesy = 4x - 7Thus, the slope-intercept form is y = 4x - 7.
8
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
4x + 2y = -8 → 2y = -4x - 8 → y = -2x - 4
4x+y = 7 y = -4x+7 in slope-intercept form So the slope is -4
4x = -3y+8 3y = -4x+8 y = -4/3x+8/3 So the slope is -4/3 or -1 and a 1/3
slope intercept form is: y=mx+b m=slope; b= y-intercept therefore, the slope of y=4x is "4"
2y - 8 = 4x; dividing by 2 gives y - 4 = 2x or y = 2x + 4. This is in slope-intercept form with slope 2 and intercept 4.
Parallel. They both have a slope of 4.
Slope = 4
The slope is 4.
The slope is 4
y+6=4x-3 y=4x-9 This is the slope intercept form: y=mx+b m (slope) = 4